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3 years ago

Please help me with number 9

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

5 0

1st one is 13 i believe
2nd one is 9

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I need help please help me with this

aliya0001 [1]

Step-by-step explanation:

first you do 8 * 1 what's 5 once you do that you'll get your answer do your other question to transfer that and I believe your answers up

7 0

3 years ago

(4+2n^3) + (5n^3+2)

pychu [463]

You just have to combine like terms here
6+7n^3 is the final answer

8 0

2 years ago

Read 2 more answers

For his birthday, Tyrone's parents gave him $7,790.00 which they put into a savings account that earns 15% interest compounded m

torisob [31]

Answer:

5 years and 5 months

Step-by-step explanation:

<u />

<u>Compound Interest Formula</u>

$\large \text{$ \sf A=P(1+\frac{r}{n})^{nt} $}$

where:

A = final amount
P = principal amount
r = interest rate (in decimal form)
n = number of times interest applied per time period
t = number of time periods elapsed

Given:

A = $17,474.00
P = $7,790.00
r = 15% = 0.15
n = 12
t = number of years

Substitute the given values into the formula and solve for t:

$\implies \sf 17474=7790\left(1+\dfrac{0.15}{12}\right)^{12t}$

$\implies \sf \dfrac{17474}{7790}=\left(1.0125}\right)^{12t}$

$\implies \sf \ln\left(\dfrac{17474}{7790}\right)=\ln \left(1.0125}\right)^{12t}$

$\implies \sf \ln\left(\dfrac{17474}{7790}\right)=12t \ln \left(1.0125}\right)$

$\implies \sf t=\dfrac{\ln\left(\frac{17474}{7790}\right)}{12 \ln \left(1.0125}\right)}$

$\implies \sf t=5.419413037...\:years$

Therefore, the money was in the account for 5 years and 5 months (to the nearest month).

3 0

1 year ago

Read 2 more answers

Triangle RST has vertices located at R (2, 3), S (4, 4), and T (5, 0).

LiRa [457]

The length of the sides are 2.24, 4.24 and 4.12 units while the slope are 0.5, -1 and -4.

<h3>Linear equation</h3>

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

For RS:

$Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(4-3)^2+(4-2)^2}=2.24 \\
\\
slope=\frac{y_2-y_1}{x_2-x_1} =\frac{4-3}{4-2}=0.5$

For RT:

$Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(0-3)^2+(5-2)^2}=4.24 \\
\\
slope=\frac{y_2-y_1}{x_2-x_1} =\frac{0-3}{5-2}=-1$

For ST:

$Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(0-4)^2+(5-4)^2}=4.12 \\
\\
slope=\frac{y_2-y_1}{x_2-x_1} =\frac{0-4}{5-4}=-4$

The length of the sides are 2.24, 4.24 and 4.12 units while the slope are 0.5, -1 and -4.

Find out more on linear equation at: brainly.com/question/14323743

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2 years ago

What is the surface area of the cube? mm2 Cube with sides of four millimeters

iris [78.8K]

2*2+4*2(1+1) that is going be your answer

7 0

3 years ago