The solution of
are 1 + 2i and 1 – 2i
<u>Solution:</u>
Given, equation is 
We have to find the roots of the given quadratic equation
Now, let us use the quadratic formula
--- (1)
<em><u>Let us determine the nature of roots:</u></em>
Here in
a = 1 ; b = -2 ; c = 5

Since
, the roots obtained will be complex conjugates.
Now plug in values in eqn 1, we get,

On solving we get,



we know that square root of -1 is "i" which is a complex number

Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i
Answer:
Step-by-step explanation:
7n^5
Answer:
2, 5, 11, 23, 47, 95, 191, 383, 767.
Step-by-step explanation:
This sequence is 2, 5, 11, 23, 47, 95, 191, 383, 767 because as you may notice, 2+ 3 =5, double the 3 to get 6. 5+ 6 =11, double the 6 to get 11 + 12 =23, etc.
Double the factor and add it to the previous term to get your next term and so forth.
Answer: 2/5y
Step-by-step explanation:

remove common factors on top and bottom
= 2/5y
Answer:
A = (1/2)(base)(height)
Step-by-step explanation:
Yes, that's correct:
A = (1/2)(base)(height)
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