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4 years ago

I tried finding the mean but it keeps saying it's wrong?

Mathematics

2 answers:

vovikov84 [41]4 years ago

6 0

Put the numbers in order from least to greatest and the number in the middle is the median. If there is two numbers in the middle add them together and divide by 2.

Bess [88]4 years ago

4 0

It’s asking you to work out the median which you have to find the middle number for.

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A football team has enough resources to recruit one player. The players the team is interested in consist of 7 wide receivers, 1

Alborosie

Answer:

I am not sure but i think it is 11/250

Step-by-step explanation:

4 0

3 years ago

689x+47x-89 dose anyone know how to solve this?

Korvikt [17]

Answer:

736x-89

Step-by-step explanation:

i think all you can do here is add the numbers that have an X in them so adding 689x+47x=736x and you leave the 89 so it becomes 736x-89

4 0

2 years ago

Read 2 more answers

Who can do it for me ????

Vikki [24]

Step-by-step explanation:

In the picture above.

Number 2 I suppose that as a straight line

so , it becomes easy to solve for y angle.

I hope that it's a clear solution.

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3 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

Salsk061 [2.6K]

Answer:

The sample size must be greater than or equal to 756

Step-by-step explanation:

The formula to calculate the error of the proportion is the following

$E=z_{\alpha/2}*\sqrt{\frac{p(1-p)}{n}}$

where p is the proportion, n the sample size, E is the error and z is the z-score for a confidence level of 95%

For a confidence level of 95% $z_{\alpha/2}=1.96$

We know that for this case $p=0.23$

We require that the error be 0.03 as maximum

Therefore we solve for the variable n

$z_{\alpha/2}*\sqrt{\frac{p(1-p)}{n}}\leq0.03\\\\1.96*\sqrt{\frac{0.23(1-0.23)}{n}}\leq0.03\\\\\sqrt{\frac{0.23(1-0.23)}{n}}\leq \frac{0.03}{1.96}\\\\(\sqrt{\frac{0.23(1-0.23)}{n}})^2\leq (\frac{0.03}{1.96})^2\\\\\frac{0.23(1-0.23)}{n}\leq (\frac{0.03}{1.96})^2\\\\\frac{0.23(1-0.23)}{(\frac{0.03}{1.96})^2}\leq n\\\\n\geq\frac{0.23(1-0.23)}{(\frac{0.03}{1.96})^2}\\\\n\geq756$

5 0

3 years ago

Read 2 more answers

In a theater there are 15 chairs in the first row, each row has 3 more chairs than the previous

andrew11 [14]

Answer:663

Step-by-step explanation:

The first row is 15,so you have to add three from the first row you and you get 18 and then you keep going and going till you get to the 17th row then you add the numbers together.

5 0

3 years ago