Answer:
182 children, 91 adults, 60 students
Step-by-step explanation:
The quantity of adults is x, then the quantity of children are 2x, the quantity of students is 333-x-2x=333-3x. The charge from all adults is 12x, students gave 7*(333-3x), children gave 5*2x=10x, the sum of all money is 2422
12x+ 7(333-3x)+10x=2422
12x+2331-21x+10x=2422
2331+x=2422
x=91- the amount of adults
1) 91*2=182- the amount of children
333-91-182= 60- the amount of students
<span>f(x) = 5x+1
f(-4) = 5(-4) + 1 = -20 + 1 = -19
hope that helps
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B: 100,000 combinations because if you have 5 digits, your equation is 10^5 which equals 100,000,
Substitute -3 for x in f(x) = 2x^2 + 4x + 10:
f(-3) = 2(-3)^2 + 4(-3) + 10 = 18 - 12 + 10 = 16 (answer)
