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andreev551 [17]
3 years ago
8

0.3x +y = 7 represents a linear function

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
7 0
Yes it represents a linear function.
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maks197457 [2]
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4 0
3 years ago
Which of the following functions are solutions of the differential equation y" – 4y' + 3y = 0? CA. y(x) = xe-3x B. y(x) = et C.
Kipish [7]

Answer:

y(x)=c_1e^{x}+c_2e^{3x}

y(x)=e^x

y(x)=e^{3x}

Option B is correct. y=e^t

Step-by-step explanation:

Given: y''-4y'+3y = 0

It is a linear differential equation.

First we make characteristic equation.

m^2-4m+3=0

Now factor the equation and we get

(m-3)(m-1)

m=1,3

Here, we have two distinct root.

y(x)=c_1e^{m_1t}+c_2e^{m_2t}

Solution of differential equation:

y(x)=c_1e^{x}+c_2e^{3x}

where, c₁ and c₂ are constants.

Hence, The solution of the given differential equation is y(x)=c_1e^{x}+c_2e^{3x}

y(x)=e^x

y(x)=e^{3x}

7 0
4 years ago
Adding and subtracting polynomials
svet-max [94.6K]

Answer:

6x^2+3x+1

Step-by-step explanation:

Simplify by combining like terms

3 0
3 years ago
Read 2 more answers
A door is 8 decimeters wide. How wide is the door in centimeters?
Sloan [31]
8 decimeters= 80 centimeters
6 0
3 years ago
Read 2 more answers
When utilizing ANOVA, what does the between group sum of squares measure?
zhenek [66]

Answer:

b. The sum of the squared deviations between each group mean and the mean across all groups

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Solution to the problem

If we assume that we have p groups and on each group from j=1,\dots,p we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2

And we have this property

SST=SS_{between}+SS_{within}

As we can see the sum of squares between represent the sum of squared deviations between each group mean and the mean across all groups.

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2

So then the best option is:

b. The sum of the squared deviations between each group mean and the mean across all groups

5 0
3 years ago
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