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Anit [1.1K]
3 years ago
11

Ishaan is 2 times as older as Chris. 35 years ago, ishaan was 7 times as old as Chris. How old is Chris?

Mathematics
1 answer:
den301095 [7]3 years ago
4 0

Answer

42

Step-by-step explanation:

Let x be Chris's age before, x+35 be Chris's age now.

2(x+35) = 35+7x

2x+70 = 35 +7x

35=5x

7=x

7+35=42

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What is the scientific notation of (1×10to the 3 power)
ale4655 [162]
That is easy its 1000
6 0
3 years ago
List the sides of triangle WXY in order from smallest to largest.
nataly862011 [7]

Answer:

Using the relation between angles and sides of any triangle the answer is:

Third option: WX, XY, YW

Step-by-step explanation:

<X=90° (right angle)

<W=51°

<Y=?

The sum of the interior angles of any triangle is 180°, then:

<W+<X+<Y=180°

Replacing the given values:

51°+90°+<Y=180°

141°+<Y=180°

Solving for <Y: Subtracting 141° both sides of the equation:

141°+<Y-141°=180°-141°

<Y=39°

The order of the angles from smallest to largest is:

<Y=39°, <W=51°, <X=90°

The opposite sides to these angles must be ordered in the same way:

Opposite side to <Y: WX

Opposite side to <W: XY

Opposite side to <X: YW

Then the order of the sides from smallest to largest is:

WX, XY, YW

6 0
4 years ago
12(6g + 2) = 12<br><br> A. 3.33<br><br> B. 1.67<br><br> C. 3.67<br><br> D. 4.3
victus00 [196]
Sorry none of those answers are right
at least to me it isnt

8 0
3 years ago
1. A family is building a circular fountain in the backyard. The yard is rectangular and measures 10x by 15x and the fountain is
sp2606 [1]
1. The remaing area of the yard will be found as follows:
Area of the yard

A1=length*width=10x*15x=150x^2 yd^2

area of the fountain
A2=πr²
A2=π(4x)²
=50.266x^2

The remaining area will be:
A=150x^2-50.266x^2
A=99.735x^2 yd^2


2] Area left for bleachers, restrooms and other parts of the stadium will be as follows:
Area of the lot is:
A1=length*width
A1=8x×12x= 96x^2 

Area of the field
A2=length×width
A2=3x×6x=18x^2

Hence the remaining area will be:
A1-A2
=96x^2-18x^2
=78x^2 sq. units


7 0
3 years ago
A circle is centered at the point (-7, -1) and passes through the point (8, 7).
Elan Coil [88]
Radius = √(7-(-1))² + (8-(-7))² = √8²+15² = √289 = 17

Let the point be (-15,y)
(-15-(-7))² + (y-(-1))² = 17²
⇒ -8² + (y+1)²  = 17²
⇒ 64 + (y+1)² = 289
⇒ (y+1)² = 289 - 64 = 225
⇒ y+1 = +15 or -15
⇒ y = +15-1    or    -15-1
⇒ y = 14    or    -16

T<span>h</span>us, the point can be either (-15,14) or (-15,-16)


3 0
4 years ago
Read 2 more answers
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