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Andre45 [30]
3 years ago
9

Let f(x) = 2x+4. If f(x) = 16, find x.

Mathematics
2 answers:
jeyben [28]3 years ago
8 0

f(x)=2x+4

And we are given that f(x)=16 and want to find the value of x. Set f(x) to 16 and we get the equation:

2x+4=16

Subtract both sides by 4

2x=12

Divide both sides by 2

x=6

This is the answer. Let me know if you need any clarifications, thanks!

Naily [24]3 years ago
8 0
Given-
f(x)=2x+4
f(x)=16
So,
=> 2x+4=16
Subtract 4 both both the sides
=>2x=12
=>x=12/2
=>x=6
So the Answer is x=6
Hope it helps you!
You might be interested in
The mean weight of an adult is 69 kilograms with a variance of 121. If 31 adults are randomly selected, what is the probability
amid [387]

Answer:

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Also, important to remember that the standard deviation is the square root of the variance.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 69, \sigma = \sqrt{121} = 11, n = 31, s = \frac{11}{\sqrt{31}} = 1.97565

What is the probability that the sample mean would be greater than 70.5 kilograms?

This is 1 subtracted by the pvalue of Z when X = 70.5. So

Z = \frac{X - \mu}{\sigma}

By the Central limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{70.5 - 69}{1.97565}

Z = 0.76

Z = 0.76 has a pvalue of 0.7764

1 - 0.7764 = 0.2236

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

8 0
3 years ago
Write as an expression " 6 times smaller than 42"​
Mademuasel [1]

Answer:

42/6 or 7

Step-by-step explanation:

5 0
2 years ago
A solid rectangular box with height 5 m and square base with side lengths 4 m is built using a lightweight material whose densit
elena55 [62]

Answer:

627200LJ

Step-by-step explanation:

Height of box=5 m

Side of square base=4 m

Volume of rectangular box=l\times b\times h

Using the formula

Volume of rectangular box=4\times 4\times 5=80m^3

Density of material=800kg/m^3

We know that

Mass=Density\times volume

Using the formula

Mass of  rectangular box=80\times 800=64000 kg

Gravity=g=9.8m/s^2

Weight of  rectangular box,F=mg=64000\times 9.8 N

Let L  be the vertical distance traveled by box

Total work done =W=F\times displacement

Therefore,total work done against gravity =64000\times 9.8 L=627200 L J

Hence, the box requires work against gravity=627200LJ

5 0
3 years ago
When Ryan started a daily exercise routine, he lost
Delicious77 [7]
Take his now weight which is 180.4. Divide it by 0.82 because 18% off is 82%. So 180.4/0.82= 220 pounds
7 0
3 years ago
4% of 73 is what? how would u solve that ima lil slow?
Svetradugi [14.3K]

Answer:

2.92

Step-by-step explanation:

4 percent *73 =

(4:100)*73 =

(4*73):100 =

292:100 = 2.92

5 0
3 years ago
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