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3 years ago

What is the equation of the line that passes through the point (-4,-2) and has a slope of -1/2?

Mathematics

1 answer:

Soloha48 [4]3 years ago

8 0

Answer:

$y = - \frac{1}{2} x$

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A refund of $3.15 on a $8.64 bill

Varvara68 [4.7K]

8.64 - 3.15 = $5.49 if this is what you are asking

5 0

3 years ago

Read 2 more answers

56.27 in expanded form

Lana71 [14]

Answer:

Step-by-step explanation:

56.27 =

+ 6

+ 0.2

+ 0.07

Expanded Factors Form:

56.27 =

5 × 10

+ 6 × 1

+ 2 × 0.1

+ 7 × 0.01

Expanded Exponential Form:

56.27 =

5 × 101

+ 6 × 100

+ 2 × 10-1

+ 7 × 10-2

Word Form:

56.27 =

fifty-six and twenty-seven hundredths

5 0

3 years ago

Justin and michelle are playing a card game. In the first round, caitlin scored 100 points and justin scored 75 points. In each

Arada [10]

Answer:

Step-by-step explanation: first you have to add up the point that each scored altogether and Caitlin scored 300 and Justin scored 250

5 0

3 years ago

Read 2 more answers

What is the equation of the line that passes through (-5, 0) and (4, 3)?

kotegsom [21]

Answer:

y = 1/3x + 5/3

Step-by-step explanation:

An equation contains a slope and y-intercept, in the form y = mx + b. To find the slope or m, you need to plug the coordinates into the slope formula.

y2 - y1/ x2 - 1

3 - 0/ 4 - (-5)

= 3 / 9

= 1/3

Now that we know the slope, we need to plug the values of x and y to find the y-intercept.

y = 1/3x + b

3 = 1/3(4) + b

3 = 4/3 + b

5/3 = b

The equation is y = 1/3x + 5/3

3 0

3 years ago

Please help! Thanks in advance.

alukav5142 [94]

In this problem, we need to plug in the given x values for $f(x)=0$ and find a and b.

When we plug in 1, we get: $2 \times {1}^{4} - 5 \times {1}^{3} - 14 \times {1}^{2} + a \times 1 + b = 0$

Simplify:
$2 - 5 - 14 + a + b = 0$
$- 17 + a + b = 0$
$a + b = 17$

We got our first statement about the values of the variables. If we find one more we can find those 2 variables.

We have another given root: 4.

Plug it in:
$2 \times {4}^{4} - 5 \times {4}^{3} - 14 \times {4}^{2} + a \times 4 + b = 0$
$512 - 320 - 224 + 4a + b = 0$
$- 32 + 4a + b = 0$
$4a + b = 32$

Now we have our second one. We can combine them:
$a + b = 17 \\ 4a + b = 32$

I use elimination method which is easier here.

Multiply the top equation by -1: $- a - b = - 17 \\ 4a + b = 32$

Add them up:
$3a = 15$

Simplify:
$a = 5$

Now we have a, we can plug in one of those equations to find b:
$5 + b = 17$
$b = 17 - 5$
$b = 12$

So, the answers are $a=5$ and $b=12$ .

6 0

3 years ago