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Andru [333]
3 years ago
10

What is 2,606 + 7,025?

Mathematics
2 answers:
trapecia [35]3 years ago
6 0

Answer: 9631

 2606

<u>+7025</u>

9631

cestrela7 [59]3 years ago
5 0

Answer:

2606 + 7025 = 9631

Pls mark me brainliest

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Nadia runs 8 miles each weekend. How many yards does Nadia run each weekend
luda_lava [24]

Answer:

14080 yds

Step-by-step explanation:

We know that 1 mile = 1760 yards

8 miles * 1760 yds/ 1 mile = (8*1760) yds=14080 yds

7 0
3 years ago
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Megan has a piece of fabric which is a right triangular shape. The length of leg 1 is 4 m. The length of the other leg is twice
Bess [88]

Answer:

8.94 m

Step-by-step explanation:

Use the Pythagorean Theorum - a^2 + b^2 = c^2. Use leg 1 as <em>a</em>, leg 2 as <em>b</em>, and the third side as <em>c</em>.

We know leg 1 is 4, and that leg 2 is twice as long as leg 1...

(4)^2 + (4*2)^2 = c^2

Now, we use the Order of Operations to find c^2...

4^2+8^2=c^2\\16+64=c^2\\80=c^2

Now, we find the square root of c^2 to find c...

\sqrt{80} =8.94

So, the length of the third side is 8.94 m.

8 0
3 years ago
George weighs twice as much as his little brother Sam.
german
74 pounds because sam weight 37
37x2 = 74
8 0
3 years ago
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Consider the line integral Z C (sin x dx + cos y dy), where C consists of the top part of the circle x 2 + y 2 = 1 from (1, 0) t
pashok25 [27]

Direct computation:

Parameterize the top part of the circle x^2+y^2=1 by

\vec r(t)=(x(t),y(t))=(\cos t,\sin t)

with 0\le t\le\pi, and the line segment by

\vec s(t)=(1-t)(-1,0)+t(2,-\pi)=(3t-1,-\pi t)

with 0\le t\le1. Then

\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)

=\displaystyle\int_0^\pi(-\sin t\sin(\cos t)+\cos t\cos(\sin t)\,\mathrm dt+\int_0^1(3\sin(3t-1)-\pi\cos(-\pi t))\,\mathrm dt

=0+(\cos1-\cos2)=\boxed{\cos1-\cos2}

Using the fundamental theorem of calculus:

The integral can be written as

\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)=\int_C\underbrace{(\sin x,\cos y)}_{\vec F}\cdot\underbrace{(\mathrm dx,\mathrm dy)}_{\vec r}

If there happens to be a scalar function f such that \vec F=\nabla f, then \vec F is conservative and the integral is path-independent, so we only need to worry about the value of f at the path's endpoints.

This requires

\dfrac{\partial f}{\partial x}=\sin x\implies f(x,y)=-\cos x+g(y)

\dfrac{\partial f}{\partial y}=\cos y=\dfrac{\mathrm dg}{\mathrm dy}\implies g(y)=\sin y+C

So we have

f(x,y)=-\cos x+\sin y+C

which means \vec F is indeed conservative. By the fundamental theorem, we have

\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)=f(2,-\pi)-f(1,0)=-\cos2-(-\cos1)=\boxed{\cos1-\cos2}

3 0
3 years ago
The difference between a number x and 18 is 22?
Elenna [48]
X-18=22
18+22=x
18+22=40
3 0
3 years ago
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