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mario62 [17]
3 years ago
14

Which sequence of a transformation will result in an image that maps onto itself? A) rotate 180 degrees counterclockwise and the

n reflect across the x axis b) reflect over the y axis and then reflect over the x axis c) rotate 180 degrees counterclockwise and then reflect across the y axis d) reflect over the y axis and then reflect again over the y axis
Mathematics
2 answers:
Firdavs [7]3 years ago
6 0

The <em>correct answer</em> is:

D) reflect over the y axis and then reflect again over the y axis.

Explanation:

Logically, if we reflect a figure across the y-axis and then reflect across the y-axis again, we have undone what we originally did, and the figure is back in its original position.

Algebraically, reflecting across the y-axis maps every point (x, y) to (-x, y). Reflecting this point across the y-axis maps (-x, y) to (x, y); this is our original point.

vesna_86 [32]3 years ago
5 0
The question is asking to choose among the following that state the sequence of a transformation will result in an image that maps onto itself, base on my research and further analysis, the answer would be <span>d) reflect over the y axis and then reflect again over the y axis. I hope you are satisfied with my answer </span>
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5<img src="https://tex.z-dn.net/?f=5%5E%7B56%7D%20x%205%5E%7B22%7D%20x%205%5E%7B-96%7D" id="TexFormula1" title="5^{56} x 5^{22}
Akimi4 [234]

Answer:

\frac{ {11}^{56} }{ {5}^{18} }

Step-by-step explanation:

{55}^{56}  \times  {5}^{22}  \times  {5}^{ - 96}

=  {55}^{56}  \times  {5}^{ - 74}

=  {11}^{56}  \times  {5}^{56}  \times  \frac{1}{ {5}^{74} }

=  {11}^{56}  \times  \frac{1}{ {5}^{18} }

=  \frac{ {11}^{56} }{ {5}^{18} }

8 0
3 years ago
The length of a violin string varies inversely with the frequency of its vibrations. A violin string 14 inches long vibrates at
lara31 [8.8K]

Answer: 525 cycles per second.

Step-by-step explanation:

The equation for inverse variation between x and y is given by :-

x_1y_1=x_2y_2       (1)

Given : The length of a violin string varies inversely with the frequency of its vibrations.

A violin string 14 inches long vibrates at a frequency of 450 cycles per second.

Let x =  length of a violin

y=  frequency of its vibrations

To find: The frequency of a 12 inch violin string.

Put x_1=14,\ x_2=12\\y_1=450,\ y_2=y in equation (1) , we get

(14)(450)=(12)(y)  

Divide both sides by 12 , we get

y=\dfrac{(14)(450)}{12}=525

Hence, the frequency of a 12 inch violin string = 525 cycles per second.

3 0
3 years ago
The area of a face of a cube is 10cm2 , find the totalof the cube​
shusha [124]

Answer:Step-by-step explanation:

tsa of cube = 6a²

                  =6*10*10

                   =600.

5 0
3 years ago
Read 2 more answers
Please help me answer this. Ty
blsea [12.9K]

I think 63, but I'm not sure, how do I delete an answer-

4 0
3 years ago
Read 2 more answers
Please help me with this problem​
AleksandrR [38]

Answer:

The answer to your question is Area = 6 u²

Step-by-step explanation:

Process

To find the area of the picture divide the figure between a square and a right triangle, determine the area of each figure and finally add them up.

1.- Calculate the area of the square

Area = side x side

        = 2 x 2

        = 4 u²

2.- Calculate the area of the triangle

Area = base x height / 2

base = 2   height = 2

Area = 2 x 2 /2

Area = 2 u₂

3.- Total area

Area = 4 + 2

       = 6 u²

3 0
4 years ago
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