Question

P^2-4p-32/p+4

Answer 1

The answer is B. p – 8; p ≠ –4

The expression is: $\frac{ p^{2}-4p-32}{p+4}$
Since the the divisor cannot be zero, that means that p+4 cannot be zero:
p + 4 ≠ 0
⇒ p ≠ -4

Let's simplify this expression:
$\frac{ p^{2}-4p-32}{p+4} = \frac{ (p+4)(p-8)}{p+4}$

Now, cancel out (p+4) and you will get:
$\frac{ (p+4)(p-8)}{p+4} = p-8$

Answer 2

P^2-4p-32=(p-8)(p+4)

$\frac{p^2-4p-32}{p+4}= \frac{(p-8)(p+4)}{p+4}=p-8$
and p must not be equal to -4


B is answer