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zheka24 [161]
2 years ago
10

A cell phone company charges $40 plus .05 per text. What is the slope?

Mathematics
1 answer:
Effectus [21]2 years ago
3 0
Y=0.05x+40
0.05x is the charge of each text
+40 is the initial charge
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Whats the prime factors of 69
SOVA2 [1]

Answer:

3  times 23 is your prime factorization. hope this helps!

Step-by-step explanation:


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10 points to the person who answers this whole thing and I will mark you as brainliest.
olga2289 [7]

Answer:

Step-by-step explanation:

Perimeter is found by adding together all the lengths of the sides. For us, that is x + (2x + 5) + (6x - 17) + (3x + 2). Now we will just combine like terms. We can also drop the parenthesis because they do nothing for us and mean nothing to the problem.

x + 2x + 5 + 6x - 17 + 3x + 2 becomes

12x - 10

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Which expression is equivalent to -3 - (-5) *
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Where are the expression.
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What symbol makes the comparison true
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For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth
murzikaleks [220]

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)


Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)


Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


Now we would set each portion equal to 0 and solve.


First root

x = 0 ---> no work needed


Second root

-x = 0 ---> divide by -1

x = 0


Third root

x - 2 = 0

x = 2


Forth root

x + 2 = 0

x = -2


Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- \sqrt{-1}

x = +/- i

7 0
3 years ago
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