The sample size of 36 will produce the widest 95% confidence interval when estimating the population parameter option (b) is correct.
<h3>What are population and sample?</h3>
It is described as a collection of data with the same entity that is linked to a problem. The sample is a subset of the population, yet it is still a part of it.
We have:
A sample has a sample proportion of 0.3.
Level of confidence = 95%
At the same confidence level, the larger the sample size, the narrower the confidence interval.
As we have a 95% confidence interval the sample size should be lower.
The sample size from the option = 36 (lower value)
Thus, the sample size of 36 will produce the widest 95% confidence interval when estimating the population parameter option (b) is correct.
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Answer:
-1/2
Step-by-step explanation:
Answer:
Assuming that all three sides are 9 inches then the answer should 729.
Step-by-step explanation:
Just multiply 9*9*9. The formula to get volume is (length)*(width)*(height).
Answer:
30 apples
Step-by-step explanation:
600 is the total number of apples (adding all numbers in the apples*frequency column). Dividing this by 20, the number of boxes, we get 30 apples as the mean number in a box.
AFC = FC / Quantity printed
<span>So given she prints 1,000 posters: AFC = 250.00/1000 = $0.25 </span>
<span>Given she prints 2,000 posters: AFC = 250.00/2000 = $0.125 </span>
<span>Given she prints 10,000 posters: AFC = 250.00/2000 = $0.025 </span>
<span>ATC = TC / Quantity printed </span>
<span>where TC = FC + Variable C * Quantity printed </span>
<span>If she prints 1000: TC = 250 + 2000*1000 = 2,000,250 </span>
<span>ATC = 2,000,250/1000 = 2000.25 </span>
<span>If she prints 2000: TC = 250 + 1600*2000 = 3,200,250 </span>
<span>ATC = 3,200,250/2000 = 1600.125 </span>
<span>If she prints 10000: TC = 250 + 1600*2000 + 1000*8000 ($1000 for each additional poster after 2000) = 11,200,250 </span>
<span>ATC = 11,200,250/10000 = 1120.025</span>
