3 years ago

Let ∠BOC=x+3, ∠AOB=4x−7, and ∠AOC=21. Solve for x.

Mathematics

1 answer:

dangina [55]3 years ago

6 0

Answer:

Step-by-step explanation:

Given the following angles ∠BOC=x+3, ∠AOB=4x−7, and ∠AOC=21, the expression is true about the angles;

∠AOC = ∠BOC+∠AOB

Substituting the given values into the expression, we will have;

21 = x+3+4x-7

collect the like terms

21 = x+4x+3-7

21 = 5x-4

Add 4 to both sides

21+4 = 5x-4+4

25 = 5x

Divide both sides by 5

5x/5 = 25/5

<em>Hence the value of x is 5</em>

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