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o-na [289]
2 years ago
15

3/4+2/3−1/8 as a mixed number in its simplest form.

Mathematics
2 answers:
aleksley [76]2 years ago
6 0

Answer:

Exact Form:

31/24

Decimal Form:

1.291¯6

Mixed Number Form:

1 7/24

Step-by-step explanation:

Elina [12.6K]2 years ago
6 0

Answer:

1 1/3

Step-by-step explanation:

3/4+2÷3-1/8

3/6÷2/8

1/3÷1/4

1/3×4/1

<em>=4/3</em>

<em>we an improper fraction,</em>

1 1/3

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Write a verbal description for each algebraic expression 100-5n
Reika [66]

Step-by-step explanation:

One hundred minus five n

6 0
3 years ago
I need to send photos.
frez [133]

SOLUTION:

Step 1:

From the given question, and comparing the scores in classes A and B

Step 2:

Question one, to know the class which had the better overall result on the exam;

(I) The scores in class A ranges from 65 to 100, while that of class B ranges from 60 to 90. This explains that class A had better results.

(ii) The median of the scores in class A is 85, while the median of the scores in class B is 75, this is another piece of supporting evidence that class A had better results.

Step 3:

Question two, to know the class which had greater variability in the results;

For a better understanding of this question, I need to explain the concept of variability in statistics.

Variability in statistics refers to the difference being exhibited by data points within a data set, as related to each other or as related to the mean. This can be expressed through the range, variance or standard deviation of a data set.

Step 4:

So we need to find the range of scores in each of the two classes and then compare, the class with the greater range has the greater variability.

The Range is the difference between the lowest and highest score (H - L), where H is the highest score and L is the lowest score.

Step 5:

Applying the formula for range stated in step 4;

For Class A; H = 100 and L = 65

For Class B; H = 90 and L = 60

The range for class A; H - L = 100 - 65 = 35

The range for class B; H - L = 90 - 60 = 30

By comparing the range of class A and that of B, it is clear that Class A had a greater range (variability)

CONCLUSION:

Class A had better overall results in the exam and greater variability in the results.

6 0
11 months ago
Find the area of a parallelogram with base b and height h b=74 cm h=14.8 cm
dexar [7]

The answer is A. 88.8 cm2

Work:

74 x 2 = 148

14.8 = 29.6

Add them = 177.6

then \frac{177.6}{2} = 88.8

5 0
3 years ago
Read 2 more answers
Find the 31st term of the following sequence.. . 9, 15, 21, .... . . 186. 189. 195. . . is there an easy way to do this.
Alja [10]
This problem is an example of an arithmetic series.

The common difference of the second term (15) with the first term (9) and the third term (21) with the second term (15) [15-9=6; 21-15=6] is 6.

The formula for solving this is:
An= A1 +(n-1)*d where An is the nth term, A1 is the first term, n is the number of terms and d is the common difference.

An=9+ (31-1)*6 = 189

The answer is 189.
7 0
3 years ago
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If x = 8 and n = 3, Evaluate the following expression: 3x - 3n + 2
Firlakuza [10]

Answer:

7

Step-by-step explanation:

3x8-3x3+2

24-3x3+2

24-9+2

15+2

=17

5 0
3 years ago
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