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elena-14-01-66 [18.8K]

3 years ago

11

If (x2 – 4) ÷ (x + 2) = x – 2, which polynomial should fill in the blank below?

1 answer:

DIA [1.3K]3 years ago

7 0

The answer is x-2 or....

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What are two ratios that are equivalent to 1:1

kow [346]

Equivalents to 1:1 -

2:2

3:3

4 0

3 years ago

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△DEF≅△PQR<br><br> What is the length of PQ?<br><br> (DF is 25cm and RQ is 24cm)

Stells [14]

Since the triangles are similar, they have the same ratio to all corresponding sides. Let's find the ratio of ΔDEF to ΔPQR.

DF/RQ = 25/24

Similarly,

DE/PQ = 25/24

Thus,

PQ = 24/25 DE
PQ = 0.96DE

This means that the length of PQ is 96% of the length of DE.

I hope I was able to help you. Have a good day.

8 0

3 years ago

10/9closest to 0,1/2or1

salantis [7]

10/9 can be simplified to 1 1/9, so it would be closer to 1

8 0

4 years ago

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5 radians is the same as _____. <br><br> Round to the nearest hundredth of a degree.

Novay_Z [31]

Answer:

286.48°

Step-by-step explanation:

Given in the question that we have to convert 5 rad to degree.

we know that,

π = 180°

1rad = 180°/π

5rad = 180°(5)/π

= 286.4788°

≈ 286.48° (nearest to hundredth)

So 5 rad is 286.48°

4 0

4 years ago

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Seven pieces of rope have an average (arithmetic mean) length of 68 centimeters and a median length of 84 centimeters. If the le

Svet_ta [14]

Answer:

The maximum possible length, in centimeters, of the longest piece of rope is 134 cm

Step-by-step explanation:

Let the seven pieces be a,b,c,d,e,f,g

Average of 7 pieces of ropes =68

$Average = \frac{\text{Sum of all lengths}}{\text{No. of pieces}}$

$68= \frac{\text{Sum of all lengths}}{7}$

$68 \times 7 =\text{a+b+c+d+e+f+g}$

$476=\text{a+b+c+d+e+f+g}$ --A

We are given that the median length of a piece of rope is 84 centimeters.

We arrange the pieces in the ascending order

So, median will be the length of 4th piece

So, d = 84 cm

the length of piece a,b,c will be less than 84 and the value of e,f,g must be greater than or equal to 84

Let us suppose the length of a,b,c be x

Let us suppose the length of e,f be 84

The length of the longest piece of rope is 14 centimeters more than 4 times the length of the shortest piece of rope

So, g = 4x+14

Substitute the value in A

$476=x+x+x+84+84+84+4x+14$

$476=7x+266$

$\frac{476-266}{7}=x$

$30=x$

g = 4x+14=4(30)+14=134

Hence the maximum possible length, in centimeters, of the longest piece of rope is 134 cm

7 0

3 years ago