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igomit [66]
3 years ago
5

The numbers 4 through 14 are placed in a bowl and draw at random then replaced after being drawn.What is the probability of draw

ing the number 14 and then a number less than 12
Mathematics
1 answer:
Sedbober [7]3 years ago
3 0

Answer:

there is a 1 in 14 chance of getting 14 and there is a 11 in 14 chance of getting a number less than 12.

Step-by-step explanation:

since there are 14 numbers, there is only one 14, so that means 1 in 14 chance. that can be written as 1:14 or 1/14. there are 14 #and 11 less than 14 so 11:14 or 11/14. unless you mean 12 or less, because then its 12/14. unless you leave the first number you drew out, then it would change to 11/13 or 12/13

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The product of 25 and an unknown number is subtracted from 36. The result is -114.
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Let x = the unknown number to get x = 6

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Find the slope of the line that goes through the points (-4, 4) and (4, 6).
Sidana [21]

Answer:

m/ 0.25

Step-by-step explanation:

dint kill me if its wrong

6 0
3 years ago
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Can anyone help i don’t know how to do it and it’s GEMDAS not PEMDAS?
Maurinko [17]
ItS PEMDAS not GEMDAS bro
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3 years ago
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20x^2-30=4x solve for x
ankoles [38]

Answer:

x=1.3288 or -1.1288

Step-by-step explanation:

Given 20x^{2}-30=4x

    Subtract 4x from both sides

         20x^{2}-4x-30=0

Since we can factor out 2 from whole equation, let's factor out 2.

         2(10x^{2}-2x-15)=0

Divide with 2 on both sides

         10x^{2}-2x-15=0

We got the quadratic equation, we can solve for x using quadratic formula.

x=\frac{-b\pm\sqrt{b^{2}-4ac} } {2a}

x=\frac{2\pm\sqrt{2^{2}-4X10X(-15)} } {2X10}

x=\frac{2\pm\sqrt{604} }{20}

x=\frac{2\pm2\sqrt{151}}{20}

x=1.3288or-1.1288


8 0
3 years ago
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I need help REALLY FAST what is the distance between the points (-1, -3 3/4) and (-1, 4 1/2) ?
kodGreya [7K]

Answer:

8 1/4

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point (-1, -3.75)

Point (-1, 4.5)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formula]:                                                         \displaystyle d = \sqrt{(-1--1)^2+(4.5--3.75)^2}
  2. [√Radical] (Parenthesis) Subtract:                                                                   \displaystyle d = \sqrt{(0)^2+(8.25)^2}
  3. [√Radical] Evaluate exponents:                                                                       \displaystyle d = \sqrt{0+68.0625}
  4. [√Radical] Add:                                                                                                 \displaystyle d = \sqrt{68.0625}
  5. [√Radical] Evaluate:                                                                                          \displaystyle d = 8.25
4 0
3 years ago
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