A=bh
1056=32<span>×b
</span>÷32 ÷32
3<span>3=h
The height is </span>3<span>3 inches.</span>
Let X be the number of burglaries in a week. X follows Poisson distribution with mean of 1.9
We have to find the probability that in a randomly selected week the number of burglaries is at least three.
P(X ≥ 3 ) = P(X =3) + P(X=4) + P(X=5) + ........
= 1 - P(X < 3)
= 1 - [ P(X=2) + P(X=1) + P(X=0)]
The Poisson probability at X=k is given by
P(X=k) = 
Using this formula probability of X=2,1,0 with mean = 1.9 is
P(X=2) = 
P(X=2) = 
P(X=2) = 0.2698
P(X=1) = 
P(X=1) = 
P(X=1) = 0.2841
P(X=0) = 
P(X=0) = 
P(X=0) = 0.1495
The probability that at least three will become
P(X ≥ 3 ) = 1 - [ P(X=2) + P(X=1) + P(X=0)]
= 1 - [0.2698 + 0.2841 + 0.1495]
= 1 - 0.7034
P(X ≥ 3 ) = 0.2966
The probability that in a randomly selected week the number of burglaries is at least three is 0.2966
True.
3 x 5 = 15
4 x 5 = 20
Therefore, 3:4 = 15:20
it is True
hope this helps
<u>Answer:</u>
The answer is B --> 
<u>How I got that:</u>
<u />
These are really easy, you're simply looking for numbers that you can factor down. Like here:
I took:

and saw that I could factor out 4 from the denominator:

and then I canceled out the common factor (4 because its on both sides):

And there ya go!
<em>~That's All Folks~</em>
<em>-Siascon</em>