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3.6.(a^5+1).b^9
18.a^6.b^9
Y^3=x and 3y=x^2 is nonlinear
the others are linear
Answer:
The answer is 4.8cm³
Step-by-step explanation:
First, you have to find the length of BC using trigonometric identities :
sinθ = oppo/hypo
cosθ = adj/hypo
tanθ = oppo/adj
Given that ∠BAC = 45° so you can use tanθ to find length of AB :
tan45° = BC/3.6
BC = 3.6×(tan45°)
= 3.6cm
Now, find the volume of pyramid using V = (1/3)×base area×h :
h = BC = 3.6cm
base area = 2×2
= 4cm²
V = (1/3)×4×3.6
= 4.8cm³
