Answer:
The equation in point - slope form of a line that passes through the points (3,-5) and (-8,4) is: y-(-5) = -(9/11) (x-3) or y+5 = -(9/11) (x-3)
Step-by-step explanation:
P1=(3,-5)=(x1,y1)→x1=3, y1=-5
P2=(-8,4)=(x2,y2)→x2=-8, y2=4
Equation in Point-Slope Form: y-y1=m(x-x1)
Slope: m=(y2-y1)/(x2-x1)
Replacing the known values:
m=[4-(-5)] / (-8-3)
m=(4+5) / (-11)
m=(9) / (-11)
m=-(9/11)
Equation in the point - slope form:
y-(-5) = -(9/11) (x-3)
y+5 = -(9/11) (x-3)
Answer:
the answer is 20
Step-by-step explanation:
180+180=360
80+70=150
180-150=20
Answer:
64
Step-by-step explanation:
this is the sequence of cube. ... hence the sequence will be 1-8-27-64-125-216.
(wen 64 is already tere)
Answer:
Step-by-step explanation:
<u><em>The question is</em></u>
How do you write an equation for a circle with center (-15,11) and radius 2?
we know that
The equation of a circle in center radius form is given by
where
(h,k) is the center of the circle
r is the radius of the circle
substitute the given vales
