Find the LCM of 121, 280 and 550.

Mathematics

1 answer:

arsen [322]1 year ago

4 0

Answer: 78

Step-by-step explanation: 78

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20 feet of ribbon, cutting ribbon into 7 1/2 inches or 6 3/4 inch lengths to make bracelets. Write an algebraic expression that

IRINA_888 [86]

ANSWER:

The algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

SOLUTION:

Given, 20 feet of ribbon, cutting ribbon into $7\frac{1}{2}$ inches or $6\frac{3}{4}$ inch lengths to make bracelets.

Let us convert the mixed fraction to improper fractions.

$7 \frac{1}{2}=\frac{7 \times 2+1}{2}=\frac{15}{2} \text { and } 6 \frac{3}{4}=\frac{6 \times 4+3}{4}=\frac{27}{4}$

Let, the length of bracelets can be made be “x”

First we have to remove the excess length of ribbon and then we have to divide the remaining with length of bracelet we want.

$\text { number of ribbons }=\frac{\text { length of ribbon-excess ribbon.}}{\text {length of bracelet}}$

$\left.=\frac{20 \text { feet }-\left\{\frac{20 \text { feep }}{x}\right.}{x} \text { [we know that, }\{x\} \text { is fractional part of } x\right$ ]

So, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$

Now, let us find the algebraic expression for feet of ribbon to make 100 ribbons.

We have 100 bracelets of length x, then total length = 100 × x

length of ribbon = 100x inches

$\begin{array}{l}{=100 \mathrm{x} \times \frac{1}{12} \text { feet }} \\\\ {=\frac{25 x}{3} \text { feet }}\end{array}$

So, the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

Hence, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

5 0

3 years ago

Hey can you please help me posted picture of question

frutty [35]

The answer is C and E

6 0

3 years ago

Read 2 more answers

Find and equation for the line that passes through the points (-6,-4) and (4,4).

Ghella [55]

We have (x-4)/(-6-4) = (y-4)/(-4-4);
(x-4)/(-10) = (y-4)/(-8);
(x-4)/5 = (y-4)/4;
4x-16 = 5y-20;
4x - 5y + 4 = 0;

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