Answer: i try my best to do
Step-by-step explanation:
Answer:
24
Step-by-step explanation:
Complete Question
Although the first quarter of 2002 was quite dismal on Wall Street, mutual funds investing in gold companies rose an average of 35.2%. Assume that the distribution of returns in the first quarter of 2002 for mutual funds specializing in gold companies is fairly symmetrical with a mean of 35.2% and a standard deviation of 20%. If random samples of 16 gold stock funds were selected:
90% of the sample mean returns are between what two values symmetrically distributed around the mean?
Answer:
The two values symmetrically distributed around the mean are
21.87\% and 43.17\%
Step-by-step explanation:
From the question we are told that
The sample size is
The sample mean is
The standard deviation is
Generally the degree of freedom is mathematically represented as
=>
=>
From the question we are told the confidence level is 90% , hence the level of significance is
=>
Generally from the t distribution table the critical value of at a degree of freedom of is
Generally the margin of error is mathematically represented as
=>
=>
Generally 90% confidence interval is mathematically represented as
=>
converting to percentage
=>
Hence the 90% of the sample mean returns are between 21.87\% and 43.17\%
Answer:
52.36%
Step-by-step explanation:
First, you need to find the radius of the circle. You can do this by using the Pythagorean theorem, which states a^2+b^2=c^2. In this case, a and b are equal to 1.2 and 1.6, and c is the radius of the circle. Plugging in we get 1.2^2+1.6^2=c^2 or 1.44+2.56=c^2 or 4=c^2. Finding the square root of both sides of the equation, we find that 2=c. Now that we have the radius, we can find the area of the circle. The area of a circle is expressed as πr^2, and plugging in 2 for r we get an area of 4π, or ~12.56637. Now all we do is divide 12,56637 by 24 and get what percentage of the area of the triangle the circle covers, which is roughly 0.5236, or 52.36%
3/5=.6
4/5=.8
1/5=.2
The answer is n=-1