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solong [7]
3 years ago
9

3. Evaluate (-2)^3 + (-5+8)/3-15

Mathematics
1 answer:
Ann [662]3 years ago
3 0
The answer to this problem would be -22
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Suppose that c(x)= (7x^3) - (84x^2) + (22,000x) is the cost of manufacturing x items. Find a production level that will minimise
ra1l [238]

Answer:

54

Step-by-step explanation:

4 0
3 years ago
Please help!!!!!!!!!!!!(15 points)​
MakcuM [25]
3 • (2x + 1) • (x + 7
3 0
2 years ago
Solve the following factorize and the en- equation of quadrate equation X² + 5x + 7 x = 0​
nlexa [21]

Answer:

{-12,0}

Step-by-step explanation:

first to solve this can collect like terms and add

X² +12x=0

and solve it by factorization method

X² +12x=0

x(x+12)=0

it means x multiplied by x = X² then x multiplied by 12 = 12x

so this means x or (x+12) equals to zero

x=0 and (x+12)=0

x+12=0

x=-12

so the solution set is {-12,0}

but can also be done by formula method

8 0
2 years ago
PLEASE HELP I ONLY HAVE AN HOUR ​
skelet666 [1.2K]

Answer:

A. I can't quite see the question, but I'm pretty sure it's A

Step-by-step explanation:

Sin(A) = 1/3

Sin^2(A) + Cos^2(A) = 1

(1/3)^2 + cos^2(A) = 1

1/9 + cos^2(A) = 1

cos^2(A) = 1 - 1/9

cos^2(A) = 8/9

cos(A) = √(8/9)

√8 = √(2 * 2 * 2) = 2√2

√9 = 3

cos(A) = 2√2/3

4 0
2 years ago
Which situation will have the greatest number of permutations?
Anton [14]

Answer:

Option C will have greatest number of permutations.

Step-by-step explanation:

A.

The number of license plates with 4 letters followed by 3 numbers, where letters and digits cannot be repeated.

We have total 26 letters (A_Z) and the letters can't be repeated. So we have 26 letter options for 1st letter

25 letters options for 2nd letter

24 letter options for 3rd letter

23 letter options for 4th letter.

So total options for 4 letters 26*25*24*23 = 358800

Now, 3 numbers are required. We have total 10 numbers (0-9)

10 number options for 1st number

9 number options for 2nd number

8 number options for 3rd number

Total options for 3 numbers= 10*9*8 = 720

total options for 4 letters and 3 numbers will be: 358800 * 720 = 258,336,000

B.

The number of license plates with 3 letters followed by 4 numbers, where letters and digits cannot be repeated.

We have total 26 letters (A_Z) and the letters can't be repeated. So we have 26 letter options for 1st letter

25 letters options for 2nd letter

24 letter options for 3rd letter

So total options for 3 letters= 26*25*24 = 15600

Now, 4 numbers are required. We have total 10 numbers (0-9)

10 number options for 1st number

9 number options for 2nd number

8 number options for 3rd number

7 number options for 4th number

Total options for 4 numbers = 10*9*8*7 = 5040

total options for 4 letters and 3 numbers will be: 15600 * 5040 = 78,624,000

C. The number of license plates with 4 letters followed by 3 numbers, where letters and digits can be repeated.

Now, the letters and digits can be repeated. So we have 26 options for each 4 letters and 10 options for each 3 numbers

26*26*26*26 *10*10*10 = 456,976 * 10,00 = 456,976,000

total options for 4 letters and 3 numbers will be: 456,976,000

D.

The number of license plates with 3 letters followed by 4 numbers, where letters and digits can be repeated.

Now, the letters and digits can be repeated. So we have 26 options for each 3 letters and 10 options for each 4 numbers

26*26*26 *10*10*10*10 = 17,576 * 10,000 = 175,760,000

total options for 3 letters and 4 numbers will be: 175,760,000

So, Option C will have greatest number of permutations.

7 0
3 years ago
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