All categories

4 years ago

What is -4-2? Help please

Mathematics

2 answers:

Marysya12 [62]4 years ago

8 0

Answer:

The answer is -6

Step-by-step explanation:

Natalija [7]4 years ago

3 0

$\bold{Hey\ there!} \\ \bold{-4-2\downarrow}\\ \bold{-4+(-2)}\\ \\ \\ \\ \bullet \bold{negative\ and\ negative = positive} \\ \bullet{\bold{positive\ and\ negative=negative}} \\ \bullet\bold{negative\ and\ positive=negative}\\ \bullet\bold{positive\ and\ positive= positive} \\ \\ \\ \boxed{\bold{This\ means\ that\ your\ answer\ will\ turn\ out\ to\ be\ a\ negative!}} \\ \\ \\ \\ \boxed{\boxed{\bold{Answer:-6(Option\ A.)\checkmark}}}$

$\bold{Good\ luck\ on\ your\ assignment\ and\ enjoy\ day!} \\ \\ \\ \frak{LoveYourselfFirst:)}$

You might be interested in

What is a four digit whole number that is divisble by 2

valentinak56 [21]

Answer:

any even number is divisible by 2.

Here's an example: 2222

There are lots of others as well.

3 0

4 years ago

Read 2 more answers

Rewrite the following integral in spherical coordinates.

lora16 [44]

In cylindrical coordinates, we have $r^2=x^2+y^2$ , so that

$z = \pm \sqrt{2-r^2} = \pm \sqrt{2-x^2-y^2}$

correspond to the upper and lower halves of a sphere with radius $\sqrt2$ . In spherical coordinates, this sphere is $\rho=\sqrt2$ .

$1 \le r \le \sqrt2$ means our region is between two cylinders with radius 1 and $\sqrt2$ . In spherical coordinates, the inner cylinder has equation

$x^2+y^2 = 1 \implies \rho^2\cos^2(\theta) \sin^2(\phi) + \rho^2\sin^2(\theta) \sin^2(\phi) = \rho^2 \sin^2(\phi) = 1 \\\\ \implies \rho^2 = \csc^2(\phi) \\\\ \implies \rho = \csc(\phi)$

This cylinder meets the sphere when

$x^2 + y^2 + z^2 = 1 + z^2 = 2 \implies z^2 = 1 \\\\ \implies \rho^2 \cos^2(\phi) = 1 \\\\ \implies \rho^2 = \sec^2(\phi) \\\\ \implies \rho = \sec(\phi)$

which occurs at

$\csc(\phi) = \sec(\phi) \implies \tan(\phi) = 1 \implies \phi = \dfrac\pi4+n\pi$

where $n\in\Bbb Z$ . Then $\frac\pi4\le\phi\le\frac{3\pi}4$ .

The volume element transforms to

$dx\,dy\,dz = r\,dr\,d\theta\,dz = \rho^2 \sin(\phi) \, d\rho \, d\theta \, d\phi$

Putting everything together, we have

$\displaystyle \int_0^{2\pi} \int_1^{\sqrt2} \int_{-\sqrt{2-r^2}}^{\sqrt{2-r^2}} r \, dz \, dr \, d\theta = \boxed{\int_0^{2\pi} \int_{\pi/4}^{3\pi/4} \int_{\csc(\phi)}^{\sqrt2} \rho^2 \sin(\phi) \, d\rho \, d\phi \, d\theta} = \frac{4\pi}3$

4 0

2 years ago

Type the correct answer in each box

Luba_88 [7]

Answer:

We know that the equation of the circle in standard form is equal to (x-h)² + (y-k)² = r² where (h,k) is the center of the circle and r is the radius of the circle.

We have x² + y² + 8x + 22y + 37 = 0, let's get to the standard form :

1 - We first group terms with the same variable :

(x²+8x) + (y²+22y) + 37 = 0

2 - We then move the constant to the opposite side of the equation (don't forget to change the sign !)

(x²+8x) + (y²+22y) = - 37

3 - Do you recall the quadratic identities ? (a+b)² = a² + 2ab + b². Now that's what we are trying to find. We call this process "completing the square".

x²+8x = (x²+8x + 4²) - 4² = (x+4)² - 4²

y²+22y = (y²+22y+11²)-11² = (y+11)²-11²

4 - We plug the new values inside our equation :

(x+4)² - 4² + (y+22)² - 11² = -37

(x+4)² + (y+22)² = -37+4²+11²

(x+4)²+(y+22)² = 100

5 - We re-write in standard form :

(x-(-4)²)² + (y - (-22))² = 10²

And now it is easy to identify h and k, h = -4 and k = - 22 and the radius r equal 10. You can now complete the sentence :)

5 0

3 years ago

A spinner has 8 sections. 2 are grey 6 are blue. The spinner is spun twice what is the probability that the first lands on grey

sweet [91]

Answe

Step-by-step explanation:

5 0

3 years ago

Solve for x and then find the measure of Angle B Angle B =

Snezhnost [94]

Answer:

Step-by-step explanation:

thanks for the points

8 0

3 years ago