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3 years ago

the sum of the measures of the central angles of a circle is 360°. Find the measures of each angle labeled x.

Mathematics

1 answer:

9966 [12]3 years ago

4 0

You would want to add all of the angles together to find the sum. Set this equal to 360.

2x-9 + 2x-9 + x + x + x = 360

Combine like terms,

7x-18 = 360

Add 18 to both sides,

7x = 378

Divvied both sides by 7,

x = 54

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Which equation represents the circle shown in the graph?

marta [7]

Answer:

i think 3

Step-by-step explanation:

8 0

3 years ago

Six more than five times a number x is at least twenty one

LUCKY_DIMON [66]

5x3=15. 15+6=21. The answer would be 3

8 0

3 years ago

Jeremy can row 3/8 of a mile in 1/4 of an hour.

Elza [17]

Answer:

3/2 mph

Step-by-step explanation:

$\frac{3}{8}$ = $\frac{r}{4}$

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6 0

3 years ago

Sort each equation according to whether it has one solution, infinitely many solutions, or no solution.

Sedaia [141]

Answer:

Equations with one solution: $-2(x-3) = 2x-6$

Equations with no solution:

$6(x+5) = 6x+11\\5(x-2) = 5x-7$

Equations with infinite many solutions: $-3(x-4) = -3x+12$

Step-by-step explanation:

We will solve each equation to see if it has one solution, no solution or infinite many solutions.

An equation where the value of variable can be found has one solution.

An equation with no solution has both sides different.

An equation with infinite solution will have both sides equal after solution(number)

So,

Equation 1:

5(x-2) = 5x-7

$5(x-2) = 5x-7\\5x-10 = 5x-7\\5x-5x = -7+10\\0 = 3$

As both sides are not equal, equation has no solution.

Equation 2:

$-3(x-4) = -3x+12\\-3x+12 = -3x+12\\-3x+3x = -12+12\\0=0\\$

As both sides are equal the equation has infinite many solutions.

Equation 3:

$-2(x-3) = 2x-6\\-2x+6 = 2x-6\\-2x-2x = -6-6\\-4x = -12\\\frac{-4x}{-4} = \frac{-12}{-4}\\x = 3$

As x=3, the equation has only one solution.

Equation 4:

$6(x+5) = 6x+11\\6x+30 = 6x+11\\6x-6x+30 = 11\\30 =11$

The equation has no solution.

Hence,

Equations with one solution: $-2(x-3) = 2x-6$

Equations with no solution:

$6(x+5) = 6x+11\\5(x-2) = 5x-7$

Equations with infinite many solutions: $-3(x-4) = -3x+12$

6 0

2 years ago

Simplify. x-2/(x^2+4x-12)

balandron [24]

Simplifying the above expression we shall proceed as follows:
x-2/(x^2+4x-12)
factoring out the denominator we get:
x^2+4x-12
=x^2-2x+6x-12
=x(x-2)+6(x-2)
=(x+6)(x-2)
thus our expression will be:
(x-2)/[(x+6)(x-2)]
simplifying the above we get:
1/(x+6)

Answer: 1/(x+6)

5 0

3 years ago