F(x)=5x^2-70x+258
Solving by completing square methods gives us:
5x^2-70x=-258
x^2-14x=-51.6
c=(b/2a)^2
c=(-14/2)^2
c=49
x^2-14x+49=-51.6+49
(x-7)(x-7)=-2.6
(x-7)^2=-2.6
multiplying through by 5 you get:
5(x-7)^2+13=0
The answer is:
A] <span>5(x − 7)2 + 13; The minimum cost to produce the product is $13. </span>
Answer:
- high tide occurs at 12 noon and 12 midnight
- Low tide occurs at 6 a.m and 6 p.m
- maximum depth value = 20 ft
- Minimum depth value = 15 ft
Step-by-step explanation:
The depth is modelled as;
y = 20 + 5 cos (πt/6)
We are told that t = 0 represents 12:00 midnight.
This is high tide because at t = 0, the cos function will be at it's maximum value of 1 since cos 0 = 1.
Max depth value is;
y = 20 + 5(0)
y = 20 ft
Minimum depth value will be the low tide and it will be when the cos function is equal to -1.
Thus;
y = 20 + 5(-1)
y = 15 ft
Since t represents number of hours and since at 12 midnight, t = 0, thus; high tide will occur again at;
12 noon
Also, let's check for low tide.
Let's try t = 6 which means 6 a.m
Thus;
y = 20 + 5 cos (π(6)/6)
y = 20 + 5 cos π
Cos π has a value of -1
Thus;
y = 20 + 5(-1)
y = 20 - 5
y = 15 ft
Thus;
Low tide occurs at 6 a.m and 6 p.m
Answer:
1000
Step-by-step explanation:
