Question

Simplify

Answer 1

The first is a. you can rewrite it
$\sqrt{x^5} = \sqrt{x^2x^2x} = \sqrt{x^2}\sqrt{x^2}\sqrt{x} = xx\sqrt{x} = x^2\sqrt{x}$

the second is d. the only common factor between 20 and 40 that can be taken out is the 4 which becomes a 2, but inside the square roots there is still a 5 and 10, which cannot be combined

the third is c.
$\sqrt{36x} + \sqrt{100x} - \sqrt{25x} \\ 6\sqrt{x}+10\sqrt{x}-5\sqrt{x} \\ 11\sqrt{x}$

the fourth is d.
add 3 to both sides $\sqrt{2x} = 10$
then square both sides $2x=100$
then divide both sides by 2, x=50