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Marat540 [252]
3 years ago
14

Simplify

Mathematics
1 answer:
guapka [62]3 years ago
3 0
The first is a. you can rewrite it
\sqrt{x^5} = \sqrt{x^2x^2x} = \sqrt{x^2}\sqrt{x^2}\sqrt{x} = xx\sqrt{x} = x^2\sqrt{x}

the second is d. the only common factor between 20 and 40 that can be taken out is the 4 which becomes a 2, but inside the square roots there is still a 5 and 10, which cannot be combined

the third is c.
\sqrt{36x} + \sqrt{100x} - \sqrt{25x} \\ 6\sqrt{x}+10\sqrt{x}-5\sqrt{x} \\ 11\sqrt{x}

the fourth is d.
add 3 to both sides \sqrt{2x} = 10
then square both sides 2x=100
then divide both sides by 2, x=50
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A new company opens and finds the profits from their first year in business is $24,000. They project the company's profits to in
Fiesta28 [93]

Answer:

$4406.7 is the profit.

explanation:

compound interest formula: \sf \large\boxed{\sf P(1+\frac{r}{100})^n }

using this formula:

\rightarrow \ \sf \sf 24000(1+\dfrac{1.7}{100})^{10} }

\rightarrow \sf \ $ \sf 28406.7

profit: $28406.7  - $24,000 = $4406.7

8 0
3 years ago
2x2 − 10x − 28 6x × 6 x − 7
Simora [160]

Answer:

no real solutions

Step-by-step explanation:

If equation is...

2x^2 - 10x - 28 = 6x(6x) - 7\\2x^2 - 10x - 28 = 6x^2 - 7\\0 = 4x^2 + 10x + 21\\4x^2 + 10x + 21 = 0

= no real solutions

7 0
3 years ago
If sec x = -2 and x is an angle in the second quadrant find tangent
faltersainse [42]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
What is the midpoint between points (15,-1),(9,-5)?
irina1246 [14]
The midpoint is their average.
.. ((15, -1) +(9, -5))/2 = ((15+9)/2, (-1-5)/2) = (12, -3)
8 0
3 years ago
Solve the system and round to the nearest hundredth. Enter the
hram777 [196]

Answer:

Step-by-step explanation:

xy = 300

x + y = 50                       Solve for y

y = 50 - x                        substitute into xy = 300

x(50 - x) = 300               Remove the brackets.

50x - x^2 = 300             Bring the left to the right.

0 = x^2 - 50x + 300

This is a quadratic. It will have 2 solutions.

a=1

b = - 50

c = 300

Put these into the quadratic equation.

It turns out that x has two values -- both plus

x1 = 42.03

x2 = 6.97

x1 + y1 = 50

42.03 + y = 50

y = 50 - 42.03

y = 7,97

(42.03 , 7.97)

====================

x2 + y2 = 50

6.97 + y2 = 50

y2 = 50 - 6.97

y2 = 43.03

(6.97 , 43.03)

6 0
3 years ago
Read 2 more answers
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