Answer:
So we know that Ms. Jan had brought the class cookies and gave out half of them the cookies she had in all was 34 she then gave the class 12 in the morning and 22 cookies was left then at lunch it she gave out 12 more so 22-12 is 10
Step-by-step explanation:
34 cookies -12=22 cookies-12=10 cookies left.
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Answer:
D. 216 cubic centimetres.
Step-by-step explanation:
The answer is D, because 6 to the 3rd power is 216. therefore, if the side length is 6, the answer is 216.
Answer:
32 cents
Step-by-step explanation:
Find 8.25 percent of 3.90:
0.0825*3.90 = 0.32
Answer:
r <= 12.6
Step-by-step explanation:
Let's calculate the rate at which he descends:
r = (46.7 - 15.2)/212 = 0.15 feet/minute
<h2>
Answer with explanation:</h2>
Confidence interval for mean, when population standard deviation is unknown:

, where
= sample mean
n= sample size
s= sample standard deviation
= Critical t-value for n-1 degrees of freedom
We assume the population has a normal distribution.
Given, n= 19 , s= 3.8 , 

A) Critical t value for
and degree of 18 freedom
= 2.8784
B) Required confidence interval:

Lower bound = 19.9 years
Uppen bound = 24.9 years
C) Interpretation: We are 99% confident that the true population mean of lies in (19.9, 24.9) .