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4vir4ik [10]
3 years ago
10

What is a reasonable estimate for the subtraction equation 3.2 − 1.4 = ________ when you round each number to the nearest whole

number? (2 points)
1
1.5
2
2.5
Mathematics
1 answer:
icang [17]3 years ago
3 0

Answer:

Hello!

After reviewing the question you have provided, I came up with the correct answer:

C) 2

Step-by-step explanation:

Firstly:

As the question states, you need to round each number to the nearest whole number and then choose the closest estimate to what the nearest solution could be.

When you round the two numbers you should come up with "3-1= ____".

This is because you round up with a number has .5 or higher, and you round down when any number has .4 or lower.

So 3.2 rounds to 3

And 1.4 rounds to 1.

With the new equation you can then solve "3-1= 2"!

Hope this helps!

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# - A circle has an area of approximately
daser333 [38]

Answer:

The area of the new circle is 804.57 cm^2

Step-by-step explanation:

In this question, we are interested in calculating the area of the new circle of the radius of the old circle was doubled.

Let’s calculate the former radius first;

Mathematically;

Area of a circle = π * r^2

Thus;

201.06 = π * r^2

r^2 = 201.06/π

r^2 = 63.999

r = √63.99

r = 8 approximately

Now let’s double this radius and it becomes 2 * 8 = 16 cm

The new area will be ;

22/7 * 16 * 16 = 804.57 cm^2

3 0
3 years ago
√(5/6)^2 plz help me
Aloiza [94]
You do 2x5=10 then x 6=12
7 0
3 years ago
Simplify 6(x + 4) 10x 6x + 4 6x + 24
Maurinko [17]

Answer:

=360x4+1440x3+24x+24

Step-by-step explanation:

6(x+4)(10)xx(6)x+(4)(6)x+24

=360x4+1440x3+(4)(6)x+24

=360x4+1440x3+24x+24

Hope it helps!!

6 0
3 years ago
Read 2 more answers
Find the area of a rectangle that has the length of 2x-3 and the width of x .Someone painted an interior area of the rectangle a
Svet_ta [14]

Answer:

The area that was not painted is (2x^{2}-6x+6)\ units^{2}

Step-by-step explanation:

step 1

Find the area of the rectangle

we know that

The area of a rectangle is equal to

A=LW

In this problem we have

L=2x-3

W=x

substitute

A=(2x-3)x\\A=(2x^{2}-3x)\ units^{2}

step 2

Find the area that was painted

A=(3)(x-2)\\A=(3x-6)\ units^{2}

step 3

Find the area that was not painted

Subtract the area that was painted from the total area of rectangle

so

A=(2x^{2}-3x)-(3x-6)=(2x^{2}-6x+6)\ units^{2}

8 0
3 years ago
Systems of equations with different slopes and different y-intercepts have one solution.
eduard
A. Always because imagine a line where one is y=x and the other is y=-x+1. The point of intersection would be (1,1)

4 0
3 years ago
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