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MAXImum [283]
2 years ago
15

The weight of oranges growing in an orchard is normally distributed with a mean weight of 6.5 oz. and a standard deviation of 1.

5 oz. Using the empirical rule, determine what interval would represent weights of the middle 99.7% of all oranges from this orchard.
Mathematics
1 answer:
sergey [27]2 years ago
6 0
Add 3 standard deviations above and below the mean to get the range in which 99.7% of the data in a normal distribution will fall
6.5 + 4.5 = 11
6.5 - 4.5 = 2
So 2 to 11 ounces would be the interval
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What is the value of the expression below when y=2 6y^2 +8y-9
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6y^2+7

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Adding and subtracting polynomials<br><br>(-3x² - 9x + 5) - ( -2x²- 4x + 7)​
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Answer:

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6 0
3 years ago
Nadia is a stockbroker. She earns 4% commission when she sells stocks. Last week, she earned $288 in commission.
Tresset [83]

Answer:

a)The total amount of her  weekly stock sales  = $7,200

b) The total amount of her yearly stock sales  = $350,000

Step-by-step explanation:

(a)  Let us assume that the total a mount of her sales in a week  = $m

      Commission earned in a week = $288

      Now, 4 % of her total sales  = $288

      or, 4% of ($m)  = $288

    ⇒\frac{4}{100}  \times  m = 288

     or, m = \frac{288 \times 100}{4}   = 7,200

     ⇒ m = $7,200

Hence, the total amount of her  weekly stock sales  = $7,200

b)  Let us assume that the total amount of her sales in a year  = $k

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Now, 4 % of her total sales  = $14,000

      or, 4% of ($k)  = $14,000

    ⇒\frac{4}{100}  \times  k = 14,000

     or, k = \frac{14,000 \times 100}{4}   = 350,000

     ⇒ k = $350,000

Hence, the total amount of her yearly stock sales  = $350,000

8 0
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