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MAXImum [283]
2 years ago
15

The weight of oranges growing in an orchard is normally distributed with a mean weight of 6.5 oz. and a standard deviation of 1.

5 oz. Using the empirical rule, determine what interval would represent weights of the middle 99.7% of all oranges from this orchard.
Mathematics
1 answer:
sergey [27]2 years ago
6 0
Add 3 standard deviations above and below the mean to get the range in which 99.7% of the data in a normal distribution will fall
6.5 + 4.5 = 11
6.5 - 4.5 = 2
So 2 to 11 ounces would be the interval
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17

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f(x)=3x+2

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Simplify (-3/5) ÷ (7/6).<br><br> A. -7/10<br> B. -18/35<br> C. 18/35<br> D 7/10
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The answer would be B. You would need to keep the first fraction, change to multiplication, and flip the second fraction and multiply across.

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3 years ago
Help me and you get 100 points and Brainliest
OlgaM077 [116]

hey someone else has already answered this!

a. To find the least squares regression equation for a group of (x,y) points:

Step 1: For each point(x,y), we need to calculate x² and xy first.

Step 2: Sum all x, y, x² and xy, which gives us Σx, Σy, Σx² and Σxy

Step 3: Calculate Slope m: m = (NΣxy − Σx Σy)/ N(Σx²) − (Σx)² , here N is the number of data.

Step 4: Calculate Intercept b: b = Σy − m(Σx)/ N

Step 5: Assemble the equation as y= mx+b

Here, we have ∑x = 120, ∑y= 1379, ∑x²= 919.5, ∑xy= 10466 and N= 16

So, m= (NΣxy − Σx Σy)/ N(Σx²) − (Σx)²

=

=

=  

= 6.33

and b = Σy − m(Σx)/ N

=

=

=

= 38.71

So, the least squares regression equation is : y= mx+b ⇒ y= 6.33x +38.71

b. When x= 8, then y= (6.33×8)+38.71 = 50.64 + 38.71 =89.35

The approximate test score of a student who sleeps an average of 8 h a night is 89.35%

EVERYTHING IS FROM sicista on brainly!

8 0
3 years ago
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Let R={0, 1, 2, 3} be the range of h(x) = x - 7. The domain of h inverse is_____.
Alecsey [184]

Answer:

{-7,-6,-5,-4}

Step-by-step explanation:

5 0
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