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babunello [35]
4 years ago
7

(07.05 MC)

Mathematics
2 answers:
AnnZ [28]4 years ago
8 0

Answer:

4p = 3 is the simplified form of the given equation

Step-by-step explanation:

Find the simplified equation

8p + 4 = − p + 7 + 2p + 3p

We need to solve for p

combine like terms

-p+2p +3p becomes 4p

8p + 4 = 4p+7

Subtract 4p from both sides

4p +4= 7

subtract 4 from both sides

4p= 3

4p = 3 is the simplified form of the given equation

postnew [5]4 years ago
3 0

Answer:

The answer is C. 4p = 3

Hope This Helps!

You might be interested in
What is 6 to the power of 2 divided by 2 times 3 plus 4
lidiya [134]
6^{2} ÷ 2*3+4

You use the order of operations with PEMDAS

P⇒Parentheses 

E⇒Exponents

M⇒Multiplication 

D⇒Division

A⇒Addition

S⇒Subtraction

6^{2} ⇒  6*6=36

36*3=108

108 ÷ 2=54

54+4=58

Answer: 58 



8 0
4 years ago
Read 2 more answers
-6+x=2x-5 what is the answer to this problem
Gnoma [55]

Answer:

x= -1

Step-by-step explanation

First move the variables to the left and change it's sign

(-6+x-2x=-5)

Then combine like terms

(-6-x=-5)

Then move the -6 to the right and combine it with the -5

(-x=-5+6)

(-x=1)

Lastly change the signs by dividing by 1

(x=-1)

8 0
4 years ago
Read 2 more answers
En un acuario compraron 30 peces y 18 tortugas de agua. Los van a colocar en peceras. Cada una tiene que haber la misma cantidad
seraphim [82]

Answer:

a) ¿Cuántas peceras compraron?

Según el cálculo anterior, la cantidad de peceras que compró es de 90 peceras.

b) ¿Cuántos peces y tortugas puede tener cada tanque?

3 peces por tanque

5 tortugas de agua por tanque

Step-by-step explanation:

Resolvemos la pregunta anterior utilizando el cálculo de múltiplo común más bajo

En un acuario compraron 30 peces y 18 tortugas de agua.

Encuentre y enumere los múltiplos de cada número hasta encontrar el primer múltiplo común. Este es el mínimo común múltiplo.

El mínimo común múltiplo es el número de tanques

Múltiplos de 18:

18, 36, 54, 72, 90, 108, 126

Múltiplos de 30:

30, 60, 90, 120, 150

Por lo tanto,

MCM (18; 30) = 90

a) ¿Cuántas peceras compraron?

Según el cálculo anterior, la cantidad de peceras que compró es de 90 peceras.

b) ¿Cuántos peces y tortugas puede tener cada tanque?

El número de peces que puede tener cada tanque = Número de tanques / Número de peces

= 90/30

= 3 peces por tanque

El número de tortugas de agua que puede tener cada tanque =

Número de tanques / Número de tortugas de agua

= 90/18

= 5 tortugas de agua por tanque

5 0
3 years ago
Can someone explain part c to me please?
Eduardwww [97]

Answer:

)  = 23 °C

ii) = 4.4° C

Step-by-step explanation:

i) The temperature on the surface of the planet.

At the surface of the planet the height is Zero

Therefore, X = 0

Thus; using the equation, the temperature, y will be;

y = 23 - 5x

y = 23 - 5(0)

  = 23 °C

ii) the temperature change for every kilometer from the surface,

From the equation;

y = 23 - 5x

we take, y to be 1

Therefore;

1 = 23 -5x , subtracting 23 on both sides we get

-22 = -5x

x = -22/-5

 = 4.4° C

4 0
4 years ago
{8x-10y=20 and -7x+10y-20
lidiya [134]

Write the equations:

8x-10y=20

-7x+10y=20

Add them using elimination

x=40

Now solve for y

8(40)-10y=20

10y=300

y=30

So there you have it: x=40, y=30.

8 0
4 years ago
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