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miv72 [106K]
3 years ago
14

Find the equation of the linethe line passes through the points (5,2) and (-4,-4)

Mathematics
1 answer:
almond37 [142]3 years ago
4 0

Answer:

y =  \frac{2}{3}x -  \frac{4}{3}

Step-by-step explanation:

first find the slope using the above points then use the slope formula to calculate the slope

m =  \frac{y2 - y1}{x2 - x1}  \\  \frac{2 - -  4}{5 -  - 4}  =  \frac{2 + 4}{5 + 4}  =  \frac{6}{9}  =  \frac{2}{3}

substitute ⅔ for m and one of the above points into the y-intercept form of the equation for a line and solve for b

y = mx + b \\ 2 =  \frac{2}{3} (5)  + b \\ 2 =  \frac{10}{3}  + b \\ 2 -  \frac{10}{3}  = b \\  \frac{6}{3}  -  \frac{10}{3}  = b \\ b =  -  \frac{4}{3}

substitute the slope and the value for b into the equation to get the answer

y =   \frac{2}{3} x -  \frac{4}{3}

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Romb ma obwód równy 32 cm. Jakie jest pole tego rombu, jeżeli jego wysokość ma 3 cm?
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Answer:

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Step-by-step explanation:

Z zadanego powyżej pytania uzyskano następujące dane:

Obwód (obwód) = 32 cm

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Następnie określimy długość boku rombu. Można to uzyskać w następujący sposób:

Obwód, czyli obwód (P) = 32 cm

Strona (y) =?

P = 4 s

32 = 4 s

Podziel obie strony przez 4

s = 32/4

s = 8 cm

Stąd długość boku rombu wynosi 8 cm

Na koniec określimy obszar rombu w następujący sposób:

Długość boków = 8 cm

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Obszar rombu (A) =?

A = sh

A = 8 × 3

A = 24 cm²

Dlatego obszar rombu jest

24 cm².

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