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Andru [333]
3 years ago
8

Add. 92 +53 Enter the correct answer in the box.

Mathematics
1 answer:
Alja [10]3 years ago
4 0

Answer:

145

Step-by-step explanation:

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A fast food restaurant executive wishes to know how many fast food meals teenagers eat each week. They want to construct a 99% c
Lana71 [14]

Answer:

The minimum sample size required to create the specified confidence interval is 2229.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

What is the minimum sample size required to create the specified confidence interval

This is n when M = 0.06, \sigma = 1.1

0.06 = 2.575*\frac{1.1}{\sqrt{n}}

0.06\sqrt{n} = 2.575*1.1

\sqrt{n} = \frac{2.575*1.1}{0.06}

(\sqrt{n})^{2} = (\frac{2.575*1.1}{0.06})^{2}

n = 2228.6

Rounding up

The minimum sample size required to create the specified confidence interval is 2229.

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3 years ago
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Answer:

B and D are the correct answers.

Step-by-step explanation:

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Step-by-step explanation:

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