Answer:
Explanation:
This is simple. I We begin by creating 2 groups of equal and opposite. The total number of elements in both group is N (if N is even) or N-1(if N is odd). The total value of both group should equal to 0. Add 0 if N is odd
We can code this function in python
def array_maker(N):
if N % 2 == 1:
if N == 1: # special case
return [0]
else:
left_ray = [i for i in range(-N//2, 1)]
right_ray = [i for i in range(N//2)]
left_ray.extend(right_ray)
return left_ray
else:
left_ray = [i for i in range(-N/2, 0)]
right_ray = [i for i in range(N/2)]
left_ray.extend(right_ray)
return left_ray