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3 years ago

If x-9 is a factor of x^2-5x-36, what is the other factor

Mathematics

1 answer:

White raven [17]3 years ago

8 0

Answer: x+4

Step-by-step explanation:

(x-9)(x+4)= x^2-5x-36

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Answer both with STEPS

Amanda [17]

Answer:

7 )

x = $\frac{3\sqrt{2} }{2}$

$y= 3$

8 )

$x=6\sqrt{6}$

$y= 9\sqrt{2}$

Step-by-step explanation:

7 ) 8)

In Δ ABC In Δ XYZ

∠ C = 45° ∠ X = 60°

∠ A = 90° ∠ Y = 90°

$AC= \frac{3\sqrt{2} }{2}$ $XY= 3\sqrt{6}$

To Find :

x = ?

y = ?

Solution:

We Know

In Δ ABC

∠ C = 45°

∠ A = 90°

∴ ∠ B = 45° ......Angle sum property of a triangle i.e 180°

∴ Δ ABC is an Isosceles Triangle

∴ AC = AB = x = $\frac{3\sqrt{2} }{2}$

Now appplying Trignometry identity we get

$\sin C = \frac{\textrm{side opposite to angle C}}{Hypotenuse}\\\\\sin 45 = \frac{AC}{BC}\\\\\frac{1}{\sqrt{2} } =\frac{\frac{3\sqrt{2} }{2}}{y}\\\\y=\frac{3\times \sqrt{2}\times \sqrt{2} }{2}\\\\y= 3$

Now In Δ XYZ

∠ X = 60°

∠ Y = 90°

∴∠ Z = 30° . .....Angle sum property of a triangle i.e 180°

Now appplying Trignometry identity we get

$\tan X = \frac{\textrm{side opposite to angle X}}{\textrm{side adjacent to angle X}}$

$\tan 60 = \frac{YZ}{XY}\\\\\sqrt{3} =\frac{y}{3\sqrt{6} }\\ y= 3\sqrt{3} \sqrt{6} \\y= 9\sqrt{2}$

Now,

$\sin X = \frac{\textrm{side opposite to angle C}}{Hypotenuse}\\\\\\\sin 60 = \frac{YZ}{XZ}\\ \\\frac{\sqrt{3} }{2} =\frac{9\sqrt{2} }{x} \\\\x=\frac{18\sqrt{2} }{\sqrt{3} } \\\textrm{after fationalizing the denominator root 3 we get}\\\\x=6\sqrt{6}$