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3 years ago

Which of the following equations represents a line with a negative slope and a negative y-intercept?

1 answer:

5 0

The answer is A because u can subtract the 3x to get 2y by itself then divide by 2 to completely get y by itself and it would be y=-3/2x - 9/2

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Solve<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3x%20%2B%204%7D%7B2%7D%20%20%3D%209.5" id="TexFormula1" title=" \frac{3x

ELEN [110]

Answer: 5

Step by step:

(3x+4)/2 = 9.5
3x+4 = 9.5*2
3x+4 = 19
3x = 19 -4
3x = 15
x = 5

7 0

3 years ago

Read 2 more answers

A trapezoid has interior angle measures of 90,90 ,75 and X degrees. Find the measure of angle x in the trapezoid. Enter only the

alexgriva [62]

The angles inside a trapezoid add up to equal 360 degrees

X = 360-90-90-75 = 105 degrees.

7 0

3 years ago

Find the area. Round to the nearest whole number.

Leona [35]

Answer:

23.

the answer is 33. But when i round its 23.

Step-by-step explanation:

7 0

3 years ago

I need help as soon as possible

bixtya [17]

I believe the correct answer is -2

7 0

4 years ago

An urn contains 8 red chips, 10 green chips, and 2 white chips. A chip is drawn and replaced, and then a second chip is drawn.

Harlamova29_29 [7]

Answer:

(A) 0.04

(B) 0.25

Step-by-step explanation:

Let R = drawing a red chips, G = drawing green chips and W = drawing white chips.

Given:

R = 8, G = 10 and W = 2.

Total number of chips = 8 + 10 + 2 = 20

$P(R) = \frac{8}{20}=\frac{2}{5}\\P(G)= \frac{10}{20}=\frac{1}{2}\\P(W)= \frac{2}{20}=\frac{1}{10}$

As the chips are replaced after drawing the probability of selecting the second chip is independent of the probability of selecting the first chip.

(A)

Compute the probability of selecting a white chip on the first and a red on the second as follows:

$P(1^{st}\ white\ chip, 2^{nd}\ red\ chip)=P(W)\times P(R)\\=\frac{1}{10}\times \frac{2}{5}\\ =\frac{1}{25} \\=0.04$

Thus, the probability of selecting a white chip on the first and a red on the second is 0.04.

(B)

Compute the probability of selecting 2 green chips:

$P(2\ Green\ chips)=P(G)\times P(G)\\=\frac{1}{2} \times\frac{1}{2}\\ =\frac{1}{4}\\ =0.25$

Thus, the probability of selecting 2 green chips is 0.25.

(C)

Compute the conditional probability of selecting a red chip given the first chip drawn was white as follows:

$P(2^{nd}\ red\ chip|1^{st}\ white\ chip)=\frac{P(2^{nd}\ red\ chip\ \cap 1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\=\frac{P(2^{nd}\ red\ chip)P(1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\= P(R)\\=\frac{2}{5}\\=0.40$

Thus, the probability of selecting a red chip given the first chip drawn was white is 0.40.

6 0

3 years ago