Answer:
- 8x^3+1 ⇒ (2x+1)(4x^2−2x+1)
- 2x^4+16x ⇒ 2x(x+2)(x^2−2x+4)
- x^3+8 ⇒ (x+2)(x^2−2x+4)
Step-by-step explanation:
The factoring of the sum of cubes is ...
a³ +b³ = (a +b)(a² -ab +b²)
1. a=2x, b=1
= (2x)³ + 1³
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2. There is an overall factor of 2x. Once that is factored out, a=x, b=2.
= (2x)(x³ +2³)
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3. a=x, b=2
= x³ +2³
Answer:
Total number of notes is 11.
Step-by-step explanation:
Value is 100 rupees…
5x + 20y = 100 and x + y = 11 are the two equations.
We can simplify…
5x + 20 y - 5x - 5y = 100 - 55 = 45
15y = 45 so y = 3
x = 11 - y = 8
So, we have 8 notes of 5 rupees denomination and 3 notes of 20 rupees denomination.
I hope it helps you.
1) rewrite the equation by completing the square
(X+4)^2=9
2) what are the solution to the equation
Answer A= X=-4 plus and minus 3
<span>Cancel <span>r2</span>
</span><span><span><span>(s4t)</span>/(</span><span>s<span>t3)</span></span></span>
2 <span>Use Quotient Rule: <span><span><span>xa/</span><span>xb</span></span>=<span>x^<span>a−b</span></span></span>
</span><span><span>s^<span>4−1</span></span><span>t^<span>1−3</span></span></span>
3 <span>Simplify <span>4−1</span> to 3
</span><span><span>s^3</span><span>t^<span>1−3</span></span></span>
4 <span>Simplify <span>1−3</span> to <span>−2</span>
</span><span><span>s^3</span><span>t^<span>−2</span></span></span>
5 <span>Use Negative Power Rule:<span><span>x^<span>−a</span></span>=<span>1/<span>xa</span></span></span>
</span><span><span>s^3</span>×<span>1/<span>t2</span></span></span>
6 <span>Simplify
</span><span><span>(s3)/(</span><span>t2)</span></span>
Done so the answer is a. then
Answer:
8y+5x
If in the case you need any other help , let me know. [ You need to pay me] :) Thanks!
