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Llana [10]
3 years ago
10

If f(x) = x^2+1 and g(x) = x-4, which value

Mathematics
1 answer:
Delicious77 [7]3 years ago
7 0
It would value to -15 because you just need to plug in the (-4) into the X
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After reading a book for English class, 100 students were asked wether or not they enjoyed it. Nine twenty-fifths of the class d
tensa zangetsu [6.8K]

Answer: 64 students

Step-by-step explanation:

What you already know : Total students in English class= 100

Nine twenty-fifths of the class did not like the book.

 

Therefore, the number of students like the book =Total students- students did not like the book

=100-36=64 students.

5 0
3 years ago
Read 2 more answers
Bart used place value and the distributive property to rewrite the expression 6(412). His work is shown below. 6(412) = 6(400 +
egoroff_w [7]

Bart should;

Multiply 6(400), 6(10), and 6(2) ⇒ 2nd

Multiply each addend by 6 ⇒ 4th

Find the sum of (2400 + 60 + 12) ⇒ 5th

Step-by-step explanation:

Let us revise the distributive property

  • a(b + c) = ab + ac
  • a(b + c + d) = ab + ac + ad

Bart used place value and the distributive property to rewrite the

expression 6(412)

His work is shown 6(412) = 6(400 + 10 + 2)

We need to know what Bart should do to find the product

∵ 6(412) = 6(400 + 10 + 2)

- Multiply each number in the bracket by 6 in the right hand side

∴ 6(400 + 10 + 2) = (6)(400) + (6)(10) + 6(2)

∴ 6(400 + 10 + 2) = 2400 + 60 + 12

∴ He should to multiply each addend by 6 and then find the sum of

  (2400 + 60 + 12)

Bart should;

Multiply 6(400), 6(10), and 6(2)

Multiply each addend by 6

Find the sum of (2400 + 60 + 12)

Learn more:

You can learn more about the place value in brainly.com/question/120752

#LearnwithBrainly

5 0
3 years ago
Read 2 more answers
Two-fifths of the students in your class are in the band. Of these, one-fourth play the saxophone.
vichka [17]

Answer:

a. 1/10 b. did not understand question

Step-by-step explanation:

It is as simple as two fifths of one fourth. (2/5) * (1/4)= 1 tenth.

3 0
3 years ago
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
PLS HELP!! In a triangle ABC, AB=3, BC=6 and AC=5. Calculate the size of the angle C.
o-na [289]
The answer to this is 8.6 repeating
6 0
3 years ago
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