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kolbaska11 [484]

3 years ago

5

PLS HELP!! In a triangle ABC, AB=3, BC=6 and AC=5. Calculate the size of the angle C.

2 answers:

o-na [289]3 years ago

6 0

The answer to this is 8.6 repeating

grigory [225]3 years ago

3 0

Answer:

he answer to this it would be 15.3

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A theatre has 50 seats on the front row. There are 4 additional seats in each following row.

alexandr402 [8]

$\boxed { \boxed { T_n = a_1 + d(n - 1)}}$

$\text {Given that }a_1 = 50 \text { and } d = 4$

$T_n = 50 + 4(n - 1)$

$T_n = 50 + 4n - 4$

$T_n = 46 + 4n$

$\boxed { \boxed {T_n = 46 + 4n }}$

When n = 20,
$T_{20} = 46 + 4(20) = 126$

$\boxed { \boxed {\text{Answer: The 20th term is 126}}}$

4 0

3 years ago

Add: 2x3 + 2x2 + 8x + 16 and -5x – 29

densk [106]

Answer:

Step-by-step explanation:

5 0

4 years ago

HELP PLS ASAP<br><br><br><br> -5 = 5/12a pls evaluate

Setler79 [48]

Answer:

a = -12

Remember that when a variable is times with a number, you <u>divide</u> the number on both sides.

When a variable is divided by a number, you <u>multiply</u> the number on both sides.

Hope this helps you. Thank you !!

6 0

3 years ago

A bag contains 35 marbles, 11 of which are red. A marble is randomly selected from the bag, and it is blue. This blue marble is

Ilia_Sergeevich [38]

Answer:

11 red + 24 blue = 35 marbles

If 1 blue is withdrawn

11 red + 23 blue = 34 marbles

P = 23 / 34 = .38 probability of drawing blue marble

6 0

3 years ago

Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v

k0ka [10]

I'll use subscript notation for brevity, i.e. $\frac{\partial f}{\partial x}=f_x$ .

By the chain rule,

$z_u=z_xx_u+z_yy_u$

$z_v=z_xx_v+z_yy_v$

$z_w=z_xx_w+z_yy_w$

We have

$z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}$

and

$\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}$

When $u=1,v=1,w=0$ , we have

$\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}$

and the partial derivatives take on values of

$\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}$

So we end up with

$\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}$

3 0

3 years ago