Answer:
Personally would go with D.
Information being shared could be both good and bad but it all would be about the situation and if it was private information or not.
The answer is encryption
steganography would be hiding data, like in an image
digital forensics is the analysis done after an attack
and the last one is a security standard
Answer: <u>Channel 16</u>. If you hear a MAYDAY call, remain silent, listen, and write down information about the boat in distress.
Hope this helps!
Answer:
D – Create a new validation rule that allows only EUR or GBP to be selected from all active currencies when an opportunity is created for these products.
Explanation:
Application containers are used to hold applications deployed to the internet during production. These containers are products of online hosting cloud services, used to control and maintain the application in production.
Access to the application's functionalities requires validation, the user must be authenticated and authorized to access certain services of the application.
Answer:
Sequence of popped values: h,s,f.
State of stack (from top to bottom): m, d
Explanation:
Assuming that stack is initially empty. Suppose that p contains the popped values. The state of the stack is where the top and bottom are pointing to in the stack. The top of the stack is that end of the stack where the new value is entered and existing values is removed. The sequence works as following:
push(d) -> enters d to the Stack
Stack:
d ->top
push(h) -> enters h to the Stack
Stack:
h ->top
d ->bottom
pop() -> removes h from the Stack:
Stack:
d ->top
p: Suppose p contains popped values so first popped value entered to p is h
p = h
push(f) -> enters f to the Stack
Stack:
f ->top
d ->bottom
push(s) -> enters s to the Stack
Stack:
s ->top
f
d ->bottom
pop() -> removes s from the Stack:
Stack:
f ->top
d -> bottom
p = h, s
pop() -> removes f from the Stack:
Stack:
d ->top
p = h, s, f
push(m) -> enters m to the Stack:
Stack:
m ->top
d ->bottom
So looking at p the sequence of popped values is:
h, s, f
the final state of the stack:
m, d
end that is the top of the stack:
m
