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3 years ago

2 root 50 + 3 root 32 + 4 root 18

Mathematics

1 answer:

Mama L [17]3 years ago

8 0

Answer:

34 root 2

Step-by-step explanation:

tell me if im wrong

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Volume of triangular prism

lukranit [14]

Answer: 225m^3

Step-by-step explanation:

Volume = Bh where "B" is the area of the base and "h" is the height

So, area of the base = 1/2(length)(height) = 1/2(5)(9) = 22.5 m^2.

Then multiply by the height.

22.5x10= 225m^3

3 0

3 years ago

ANYONE SOMEONE PLEASE

ladessa [460]

Answer:

I'm fairly positive the answer is 90 degrees.

4 0

4 years ago

Which expression is equivalent to (3a)-2? O o 3a2 ܝ | ܝ | ܚ| ܘ ܩ|ܛܘ

Bad White [126]

Number 1 is correct 1/9a2

6 0

3 years ago

What is the x intercept of the line

Mrrafil [7]

B -7,0 when we talk about the x intercept we talk about where the line touches the x axis which would be the horizontal line , in this graph we saw the graphed line touches the x axis on -7 therefore , the x intercept is -7,0

3 0

3 years ago

The Institute of Education Sciences measures the high school dropout rate as the percentage of 16- through 24-year-olds who are

STALIN [3.7K]

Answer:

We conclude that the proportion of dropouts has changed from the historical value of 0.081.

Step-by-step explanation:

We are given that in 2009, the high school dropout rate was 8.1%. A polling company recently took a survey of 1000 people between the ages of 16 and 24 and found 6.5% of them are high school dropouts.

The polling company would like to determine whether the proportion of dropouts has changed from the historical value of 0.081.

Let p = proportion of school dropouts rate

SO, Null Hypothesis, $H_0$ : p = 0.081 {means that the proportion of dropouts has not changed from the historical value of 0.081}

Alternate Hypothesis, $H_A$ : p $\neq$ 0.081 {means that the proportion of dropouts has changed from the historical value of 0.081}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of high school dropout rate = 6.5%

n = sample of people = 1000

So, test statistics = $\frac{0.065-0.081}{{\sqrt{\frac{0.065(1-0.065)}{1000} } } } }$

= -2.05

Also, P-value is given by the following formula;

P-value = P(Z < -2.05) = 1 - P(Z $\leq$ 2.05)

= 1 - 0.97982 = 0.0202 or 2.02%

Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test. Since our test statistics does not lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the proportion of dropouts has changed from the historical value of 0.081.

7 0

4 years ago