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rusak2 [61]
3 years ago
15

On a rectangular coordinate plane, a circle centered at (0, 0) is inscribed within a square with adjacent vertices at (0, -2√) a

nd (2√, 0). What is the area of the region, rounded to the nearest tenth, that is inside the square but outside the circle?

Mathematics
1 answer:
Pani-rosa [81]3 years ago
7 0

Answer:

  0.9 square units

Step-by-step explanation:

We assume you intend the vertices of the square to be (±√2, 0) and (0, ±√2). Then the diagonals of the square are 2√2 in length and its area is ...

  (1/2)(2√2)² = 4

The radius of the inscribed circle is 1, so its area is ...

  π·1² = π

and the area outside the circle, but inside the square is the difference of these areas:

  area of interest = 4 - π ≈ 0.858407

  area of interest ≈ 0.9

You might be interested in
A flock of geese is flying north for the summer while a bird watcher is observing. He notices that they are flying in the shape
nata0808 [166]

Answer:

y = -¼│x − 5│+ 3

Step-by-step explanation:

y = a│x − h│+ k

(h, k) is the vertex of the absolute value graph.  In this case, it's (5, 3).

y = a│x − 5│+ 3

One point on the graph is (1, 2).  Plug in to find the value of a.

2 = a│1 − 5│+ 3

2 = 4a + 3

a = -¼

Therefore, the graph is:

y = -¼│x − 5│+ 3

4 0
3 years ago
Helpppppppppppppppppppppppppppppppppppppppppp
zimovet [89]
Answer:
First choice is the correct one

Explanation:
The given is:
[(x+5) / (x+2)] - [(x+1) / x(x+2)]
First, we will need to have a common denominator and then we will solve the subtraction normally. To get a common denominator, we will have to multiply both numerator and denominator of first term by x.

Therefore:
[(x+5) / (x+2)] - [(x+1) / x(x+2)] = [x(x+5) / x(x+2)] - [(x+1) / x(x+2)]
                                                 = [x(x+5)-(x+1)] / [x(x+2)]
                                                 = (x^2 + 5x - x - 1) / [x(x+2)]
                                                 = [(x^2 + 4x - 1)] / [x(x+2)]

Hope this helps :)

3 0
3 years ago
How would you solve this? Please give an explanation.
Neporo4naja [7]

The <em>first three</em> elements of the <em>recursive</em> series are 6, 10, 8. (Correct choice: B)

<h3>How to generate values from a recursive function</h3>

In this question we have a kind of <em>recursive</em> function known as Fibonacci's function, where a value of the series is generated from at least <em>immediately previous</em> elements. In this case, we need to find the <em>first</em> three elements from the <em>fifth</em> and <em>fourth</em> elements of the series:

a_{n-2} = a_{n-1} - a_{n} + 4

a₄ = a₅ - a₆ + 4

a₄ = - 2 - 0 + 4

a₄ = 2

a₃ = a₄ - a₅ + 4

a₃ = 2 - (- 2) + 4

a₃ = 8

a₂ = a₃ - a₄ + 4

a₂ = 8 - 2 + 4

a₂ = 10

a₁ = a₂ - a₃ + 4

a₁ = 10 - 8 + 4

a₁ = 6

The <em>first three</em> elements of the <em>recursive</em> series are 6, 10, 8. (Correct choice: B)

To learn more on recursive series: brainly.com/question/8972906

#SPJ1

4 0
2 years ago
A boat travels for 4 hours at a constant speed of 35. 25 km/h. How far does the boat travel? 105 km 120 km 141 km 352 km.
AleksandrR [38]

Answer:

12 hours(105km)

13.64 hours (120 km)

16 hours (141 km)

40 hours ( 352km)

8 0
2 years ago
Need to find the equation for the line with the given properties. Express your answer using either the general form or the slope
Phoenix [80]

To answer this question we will use the following slope-point formula for the equation of a line:

y-y_1=m(x-x_1)\text{.}

Therefore, the equation of the line that has a slope of 1/3 and passes through the point (-3,3) is:

y-3=\frac{1}{3}(x-(-3))\text{.}

Simplifying the above equation we get:

\begin{gathered} y-3=\frac{1}{3}(x+3), \\ y-3=\frac{1}{3}x+1. \end{gathered}

Adding 3 to the above equation we get:

\begin{gathered} y-3+3=\frac{1}{3}x+1+3, \\ y=\frac{1}{3}x+4. \end{gathered}

Answer:

y=\frac{1}{3}x+4.

4 0
1 year ago
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