On a rectangular coordinate plane, a circle centered at (0, 0) is inscribed within a square with adjacent vertices at (0, -2√) a
nd (2√, 0). What is the area of the region, rounded to the nearest tenth, that is inside the square but outside the circle?
1 answer:
Answer:
0.9 square units
Step-by-step explanation:
We assume you intend the vertices of the square to be (±√2, 0) and (0, ±√2). Then the diagonals of the square are 2√2 in length and its area is ...
(1/2)(2√2)² = 4
The radius of the inscribed circle is 1, so its area is ...
π·1² = π
and the area outside the circle, but inside the square is the difference of these areas:
area of interest = 4 - π ≈ 0.858407
area of interest ≈ 0.9
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Answer:
Step-by-step explanation:
If we have a linear function of the form ,
- Vertical translation of c units up means:
f(x) = ax - b + c
- Vertical translation of d units down means:
f(x) = ax - b - d
- Horizontal translation of c units right means:
f(x) = a(x-c) - b
- Horizontal translation of d units left means:
f(x) = a(x+d) - b
These are the horizontal/vertical translation rules. For the function shown, we apply the first rule and it becomes:
This would be the new equation of the translated function.