On a rectangular coordinate plane, a circle centered at (0, 0) is inscribed within a square with adjacent vertices at (0, -2√) a
nd (2√, 0). What is the area of the region, rounded to the nearest tenth, that is inside the square but outside the circle?
1 answer:
Answer:
0.9 square units
Step-by-step explanation:
We assume you intend the vertices of the square to be (±√2, 0) and (0, ±√2). Then the diagonals of the square are 2√2 in length and its area is ...
(1/2)(2√2)² = 4
The radius of the inscribed circle is 1, so its area is ...
π·1² = π
and the area outside the circle, but inside the square is the difference of these areas:
area of interest = 4 - π ≈ 0.858407
area of interest ≈ 0.9
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Formula of v. of sphere = (<span><span>4</span>π</span>r
)/3<span>
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pi = 3
(4 x 3 x </span>
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Answer = 110cm
r = 3
pi = 3
(4 x 3 x </span>
Answer = 110cm
Answer:
Step-by-step explanation:
<h3> The complete exercise is attached.</h3><h3></h3>The area of a rectangle can be calculated with this formula:
Where "l" is the lenght and "w" is the width.
Then, you can notice that it can be obtained by multiplying the dimensions of the rectangle.
Knowing this, you can determine that the total area of the two flowers bed can be obtained by adding the products of their dimensions.
Since one of the rectangular flower bed is 2.78 feet by 4.81 feet and the other bed 2.78 feet by 5.61 feet, you can write the following expression to find the total area (in square feet)of the two beds:
If you factor out 2.78:
or
Therefore, the expression that does not represent the total area in square feet of the two beds, is:
