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SVETLANKA909090 [29]

2 years ago

5

Prove that : 1/1-secA + 1/1+secA = -2cot^2A

1 answer:

irina1246 [14]2 years ago

7 0

Answer:

Step-by-step explanation:

LHS = 1/1-secA + 1/1+secA

$= \frac{1*(1+Sec A)}{(1-Sec A)(1+Sec A)}+\frac{1*(1-Sec A)}{(1+Sec A)*(1-Sec A)}\\\\=\frac{(1+Sec A)}{1-Sec^{2} A}+\frac{(1-Sec A)}{1-Sec^{2} A}\\\\=\frac{1+Sec A+1-Sec A}{(1-Sec^{2} A)}\\\\= \frac{2}{(1-Sec^{2} A)}\\\\=\frac{2}{-(Sec^{2} A - 1)}\\\\= \frac{-2}{Tan^{2} A}\\\\= -2Cot^{2} A$

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Vadim26 [7]

Answer:

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2 years ago

One hundred adults were asked to name their favorite sport and the results are shown in the circle graph. What percent of adults

vlada-n [284]

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3 years ago

Find K: mx=p(z/x+k + 2s/y)

ivann1987 [24]

Answer:

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2 years ago

Plot the following points to create a rectangle.

Tanya [424]

Answer:

(5, -1)

Step-by-step explanation:

The three coordinates of a triangle are given as:

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Let us label the vertices:

A (5,3),

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C(-5,-1).

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Let us consider the side AB, we can see that only x coordinate is changed from A to B.

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Same pattern will be followed in CD as that of AB.

x coordinate will be changed by same difference as that of AB.

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Equating them:

$-5-x=-10\\\Rightarrow x = 5$

Same pattern is followed in BC and AD.

Their change in y coordinate will be same.

$-1-3=y-3\\\Rightarrow y =-1$

Missing vertex is <em>(5, -1)</em>.

Please refer to the attached image for the rectangle.

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8_murik_8 [283]

Answer:

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