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SVETLANKA909090 [29]
3 years ago
5

Prove that : 1/1-secA + 1/1+secA = -2cot^2A​

Mathematics
1 answer:
irina1246 [14]3 years ago
7 0

Answer:

Step-by-step explanation:

LHS = 1/1-secA + 1/1+secA

       = \frac{1*(1+Sec A)}{(1-Sec A)(1+Sec A)}+\frac{1*(1-Sec A)}{(1+Sec A)*(1-Sec A)}\\\\=\frac{(1+Sec A)}{1-Sec^{2} A}+\frac{(1-Sec A)}{1-Sec^{2} A}\\\\=\frac{1+Sec A+1-Sec A}{(1-Sec^{2} A)}\\\\= \frac{2}{(1-Sec^{2} A)}\\\\=\frac{2}{-(Sec^{2} A - 1)}\\\\= \frac{-2}{Tan^{2} A}\\\\= -2Cot^{2} A

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==================================================

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