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3 years ago

Prove that : 1/1-secA + 1/1+secA = -2cot^2A

Mathematics

1 answer:

irina1246 [14]3 years ago

7 0

Answer:

Step-by-step explanation:

LHS = 1/1-secA + 1/1+secA

$= \frac{1*(1+Sec A)}{(1-Sec A)(1+Sec A)}+\frac{1*(1-Sec A)}{(1+Sec A)*(1-Sec A)}\\\\=\frac{(1+Sec A)}{1-Sec^{2} A}+\frac{(1-Sec A)}{1-Sec^{2} A}\\\\=\frac{1+Sec A+1-Sec A}{(1-Sec^{2} A)}\\\\= \frac{2}{(1-Sec^{2} A)}\\\\=\frac{2}{-(Sec^{2} A - 1)}\\\\= \frac{-2}{Tan^{2} A}\\\\= -2Cot^{2} A$

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anzhelika [568]

Answer:

$x=\frac{1}{4}$

Step-by-step explanation:

$81^{x+1}+3^{4x}=246$

$81=3^4$

Rewrite equation: $3^{4\left(x+1\right)}+3^{4x}=246$

$3^{4\left(x+1\right)}=3^{4x}\times 3^4$

$3^{4x}\times 3^4+3^{4x}=246$

Factor out $3^{4x}$ :

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Divide both sides by $(3^4+1)$ :

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$3^{4x}=\frac{246}{3^4+1}$

$3^{4x}=\frac{246}{82}$

$3^{4x}=3$

Anything to the power of 1 is itself. Hence,

$4x=1\\$

$x=\frac{1}{4}$

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4 years ago

Find f(x) and g(x) so the function can be expressed as y = f(g(x)). y = Two divided by x squared. + 3

kodGreya [7K]

Hello,

g(x)=x²+3
f(x)=2/x
so f(g(x))=f(x²+3)=2/(x²+3)

Explainations:

f(y)=2/y
f(4y)=2/(4y)
f(x²)=2/x²
f(x²+3)=2/(x²+3)

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LMNP is rotated 180 degrees clockwise around the origin. What are the coordinates of L?

Alona [7]

$\huge\boxed{L^\prime(0, -1)}$

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$L(0, 1)$

$L^\prime(0*(-1), 1*(-1))\\\boxed{L^\prime(0, -1)}$

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find the sum of a 9-term geometric sequence when the first term is 4 and the last term is 1,024 and select the correct answer be

olasank [31]

Hello,

$u_{1} =4\\
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$

Answer B (but see the problem)

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valina [46]

Answer:

Step-by-step explanation:

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Prove that : 1/1-secA + 1/1+secA = -2cot^2A​

Prove that : 1/1-secA + 1/1+secA = -2cot^2A