There are no properties because you can do anything with subtraction and division
Let p be
the population proportion. <span>
We have p=0.60, n=200 and we are asked to find
P(^p<0.58). </span>
The thumb of the rule is since n*p = 200*0.60
and n*(1-p)= 200*(1-0.60) = 80 are both at least greater than 5, then n is
considered to be large and hence the sampling distribution of sample
proportion-^p will follow the z standard normal distribution. Hence this
sampling distribution will have the mean of all sample proportions- U^p = p =
0.60 and the standard deviation of all sample proportions- δ^p = √[p*(1-p)/n] =
√[0.60*(1-0.60)/200] = √0.0012.
So, the probability that the sample proportion
is less than 0.58
= P(^p<0.58)
= P{[(^p-U^p)/√[p*(1-p)/n]<[(0.58-0.60)/√0...
= P(z<-0.58)
= P(z<0) - P(-0.58<z<0)
= 0.5 - 0.2190
= 0.281
<span>So, there is 0.281 or 28.1% probability that the
sample proportion is less than 0.58. </span>
Step-by-step explanation:
0.075 % is the probability of that
Answer:
B)max/ opens down
Step-by-step explanation:
Parabola equation:
The equation of a parabola has the following format:

If
, that is, x² is multiplied by a positive number, the function has a minimum value and the parabola opens up.
If
, that is, x² is multiplied by a negative number, the function has a maximum value and the parabola opens down.
In this question:

From the graph, we already see that it opens down and has a max, and analitically, since
, this is confirmed. The correct answer is given by option b.
Answer: a) 
Step-by-step explanation:
Since we have given that

a.) Find the inverse of f(x) and name it g(x).
Let f(x) = y
So, it becomes
Switching x to y , we get


b) . Use composition to show that f(x) and g(x) are inverses of each other.

Similarly,

so, both are inverses of each other.
c) Draw the graphs of f(x) and g(x) on the same coordinate plane.
As shown below in the graph , Since for inverse function we need an axis of symmetry i.e. y=x
And both f(x) and g(x) are symmetry to y=x.
∴ f(x) and g(x) are inverses of each other.