Question

Write an equation for a line that is perpendicular to y = -4x + 2 and passes through the point (-8, 5).

Answer 1

Answer:

y=1/4x + 7

Step-by-step explanation:

To find the perpendicular equation of an equation, you need to find the reciprocal of the slope (reciprocal is the opposite fraction and it's opposite sign (negative or positive)). Then you use both points in the point slope form. y-y1=m(x-x1), y-5=m(x--8), subtracting -8 from x is the same as +8, so the equation becomes y-5=m(x+8), m is the slope and our new slope is 1/4 (the reciprocal of -4x). Now your equation is y-5=1/4(x+8). All you have to do now is solve. first you multiply 1/4 by x and 8 to get rid of the parenthesis. so the equation is now y-5=1/4x+2. Now you move the 5 to the other side, so it becomes a +5 instead of -5, and you add it to 2. now the equation is y=1/4x+7.