An arborist wants to prune an oak tree that has grown too tall. The arborist takes a 15-foot ladder and places it on a horizonta
l surface on the ground so it leans against the tallest part of the tree trunk. If the bottom part of the ladder makes an angle of 70 degrees with respect to the ground, what is the distance between the ladder and the tree trunk?
1 answer:
See the attached picture to better understand the problem
we know that
in the right triangle ABC
cos 70=adjacent side angle 70/hypotenuse
adjacent side angle 70=BC----> <span>distance between the ladder and the tree trunk
hypotenuse=AC------> 15 ft
cos 70=BC/AC-------> solve for BC
BC=AC*cos 70------> BC=15*cos 70-----> BC=5.13 ft
the answer is
the </span>distance between the ladder and the tree is 5.13 ft<span>
</span>
we know that
in the right triangle ABC
cos 70=adjacent side angle 70/hypotenuse
adjacent side angle 70=BC----> <span>distance between the ladder and the tree trunk
hypotenuse=AC------> 15 ft
cos 70=BC/AC-------> solve for BC
BC=AC*cos 70------> BC=15*cos 70-----> BC=5.13 ft
the answer is
the </span>distance between the ladder and the tree is 5.13 ft<span>
</span>
You might be interested in
Answer:
The best choice would be hiring a random employee from company A
Step-by-step explanation:
<em>Supposing that the performance rating of employees follow approximately a normal distribution on both companies</em>, we are interested in finding what percentage of employees of each company have a performance rating greater than 5.5 (which is the mean of the scale), when we measure them in terms of z-scores.
In order to do that we standardize the scores of both companies with respect to the mean 5.5 of ratings
The z-value corresponding to company A is
where
= mean of company A
= 5.5 (average of rating between 1 and 10)
s = standard deviation of company A
We do the same for company C
This means that 27.49% of employees of company C have a performance rating > 5.5, whereas 71.42% of employees of company B have a performance rating > 5.5.
So, the best choice would be hiring a random employee from company A