Answer:
Domain: {-4, -2, 0, 2, 4}
Range: {-2, -1, 0 1, 2}
Step-by-step explanation:
<u>Corrected Question</u>
Is the function given by:
continuous at x=4? Why or why not? Choose the correct answer below.
Answer:
(D) Yes, f(x) is continuous at x = 4 because
Step-by-step explanation:
Given the function:
A function to be continuous at some value c in its domain if the following condition holds:
- f(c) exists and is defined.
- exists.
At x=4
Therefore:
By the above, the function satisfies the condition for continuity.
The correct option is D.
The method of multiplication shown is (a) Ancient Egyptian Method
<h3>Multiplication</h3>
This involves taking the product of at least two factors which could be numbers, expressions or both
From the method shown, we can see that a factor is multiplied by multiples of 2 (i.e. doubling), till it reaches a maximum
This method is associated with the Egyptian.
Hence, the method of multiplication is (a) Ancient Egyptian Method
Read more about multiplications at:
brainly.com/question/10873737
1/4x - 2 = 3/8
First, to start solving this, we can rearrange our fraction. Let's take 1/4x and change it to x/4. Why? Well, a variable can also be considered as the number 1.
Second, now we can continue solving for our variable (x). Let's add 2 to each side.
Third, let's simplify 3/8 + 2. (3/8 + 2 = 2.375 =19/8)
Fourth, continue trying to get the variable by itself. Multiply each side by 4.
Fifth, let's simplify 19/8 × 4. This is simple. Leave the denominator be and just do 19 × 4, which equals 76.
Sixth, our final step is to simplify our fraction. To do so, we will need to list the factors of the numerator and denominator and find the greatest common factor (GCF).
Factors of 76: 1, 2, 4, 19, 38, 76
Factors of 8: 1, 2, 4, 8
Since 4 is our first common factor, it is considered our GCF.
Seventh, now let's divide. Divide both the numerator and denominator by the GCF (4) to create our new simplified fraction.
Answer in fraction form:
Answer in decimal form:
The area of a rhombus is half of the product of the lengths of the diagonals.
area = (7.5 yd + 7.5 yd)(13 yd + 13 yd)/2
area = (15 yd)(26 yd)/2
area = 390 yd^2/2
area = 195 yd^2
Answer: 195