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3 years ago

This isn't a question, just a tip!

Mathematics

1 answer:

masya89 [10]3 years ago

3 0

Aww thank you. Im pretty sure you helped people cause you helped me :) I hope you have an amazing day!

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I’m not good at solving for any letters, if you give me a head start of how to solve I’ll solve, I just can’t seem to learn how

olga_2 [115]

Okay, so on this type of question, the exterior angle equals the two interior angles added up, so you take 4x+7+6x-9=118 and then solve!

x=12 :)

6 0

3 years ago

an odd interger can be represented by the expression n+ 2 where n is any odd integer find three consecutive odd intergerss that

Katarina [22]

Answer:

-15,-13,-11

n + (n+2) + (n+4) = -51

3n + 6 = -51

3n = -57

n = -19

-19,-17,-15

Step-by-step explanation:

5 0

3 years ago

Emerson struck out 112 times in 350 at-bats. Write a proportion to represent the percent of strike outs per at-bats.

Alex Ar [27]

Answer:

32% of his bats were stuck out.

Step-by-step explanation:

emerson struck out 112 times out of the total of 350 times. therefore, this can be represented as the fraction 112/350, which can be simplified to 8/25.

8 0

3 years ago

What is 40+1+0.2+0.003 written in expanded form

lubasha [3.4K]

Answer:400000 + 10000 + 9000 + 200 + 40 + 7

Step-by-step explanation:

6 0

3 years ago

According to a study done by a university student, the probability a randomly selected individual will not cover his or her mou

VikaD [51]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$P(X = 8) = 0.0037$

$P(X < 5) = 0.805$

$P(X > 6) = 0.0206$

I would be surprised because the value is very small , less the 0.05

Step-by-step explanation:

From the question we are told that

The probability a randomly selected individual will not cover his or her mouth when sneezing is $p = 0.267$

Generally data collected from this study follows binomial distribution because the number of trials is finite , there are only two outcomes, (covering , and not covering mouth when sneezing ) , the trial are independent

Hence for a randomly selected variable X we have that

$X \ \ \~ \ \ { B ( p , n )}$

The probability distribution function for binomial distribution is

$P(X = x ) = ^nC_x * p^x * (1 -p) ^{n-x}$

Considering question a

Generally the the probability that among 12 randomly observed individuals exactly 8 do not cover their mouth when sneezing is mathematically represented as

$P(X = 8) = ^{12} C_8 * (0.267)^8 * (1- 0.267)^{12-8}$

Here C denotes combination

$P(X = 8) = 495 * 0.000025828 * 0.28867947$

$P(X = 8) = 0.0037$

Considering question b

Generally the probability that among 12 randomly observed individuals fewer than 5 do not cover their mouth when sneezing is mathematically represented as

$P(X < 5 ) =[P(X = 0 ) + \cdots + P(X = 4)]$

=> $P(X < 5 ) =[ ^{12} C_0 * (0.267)^0 * (1- 0.267)^{12-0} + \cdots + ^{12} C_4 * (0.267)^4 * (1- 0.267)^{12-4} ]$

=> $P(X < 5 ) = 0.02406 + 0.10516 + 0.21067 + 0.25580 + 0.20964$

=> $P(X < 5) = 0.805$

Considering question c

Generally the probability that fewer than half(6) covered their mouth when sneezing(i.e the probability the greater than half do not cover their mouth when sneezing) is mathematically represented as

$P(X > 6) = 1 - p(X \le 6)$

=> $P(X > 6) = 1 - [P(X = 0) + \cdots + P(X =6)]$

=> $P(X > 6)=1 - [^{12} C_0 * (0.267)^0 * (1- 0.267)^{12-0}+ \cdots + ^{12} C_4 * (0.267)^6 * (1- 0.267)^{12-6} ]$

=> $P(X > 6)= 1 - [0.02406 + \cdots + 0.0519 ]$

=> $P(X > 6) = 0.0206$

I would be surprised because the value is very small , less the 0.05

8 0

4 years ago