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11111nata11111 [884]
3 years ago
5

The retention of encoded information over time is called storage. A measure of memory storage that involves identifying informat

ion previously learned is ___.
Computers and Technology
1 answer:
Anni [7]3 years ago
7 0

Answer: ask google and search quizlet by it , it will show you

Explanation:

You might be interested in
Computer Networks - Queues
lyudmila [28]

Answer:

the average arrival rate \lambda in units of packets/second is 15.24 kbps

the average number of packets w waiting to be serviced in the buffer is 762 bits

Explanation:

Given that:

A single channel with a capacity of 64 kbps.

Average packet waiting time T_w in the buffer = 0.05 second

Average number of packets in residence = 1 packet

Average packet length r = 1000 bits

What are the average arrival rate \lambda in units of packets/second and the average number of packets w waiting to be serviced in the buffer?

The Conservation of Time and Messages ;

E(R) = E(W) + ρ

r = w + ρ

Using Little law ;

r = λ × T_r

w =  λ × T_w

r /  λ = w / λ  +  ρ / λ

T_r =T_w + 1 / μ

T_r = T_w +T_s

where ;

ρ = utilisation fraction of time facility

r = mean number of item in the system waiting to be served

w = mean number of packet waiting to be served

λ = mean number of arrival per second

T_r =mean time an item spent in the system

T_w = mean waiting time

μ = traffic intensity

T_s = mean service time for each arrival

the average arrival rate \lambda in units of packets/second; we have the following.

First let's determine the serving time T_s

the serving time T_s  = \dfrac{1000}{64*1000}

= 0.015625

now; the mean time an item spent in the system T_r = T_w +T_s

where;

T_w = 0.05    (i.e the average packet waiting time)

T_s = 0.015625

T_r =  0.05 + 0.015625

T_r =  0.065625

However; the  mean number of arrival per second λ is;

r = λ × T_r

λ = r /  T_r

λ = 1000 / 0.065625

λ = 15238.09524 bps

λ ≅ 15.24 kbps

Thus;  the average arrival rate \lambda in units of packets/second is 15.24 kbps

b) Determine the average number of packets w waiting to be serviced in the buffer.

mean number of packets  w waiting to be served is calculated using the formula

w =  λ × T_w

where;

T_w = 0.05

w = 15238.09524 × 0.05

w = 761.904762

w ≅ 762 bits

Thus; the average number of packets w waiting to be serviced in the buffer is 762 bits

4 0
3 years ago
What is a characteristic of an open software license
Darya [45]

Answer: Something people can change and share. It is usually given the bad name of have a bunch of fake information and bugs. Wikipedia is a good example of an open source website but it is not a program.

Explanation: An open source program is a program where you have free rein to basically do whatever you want to it.

3 0
3 years ago
So I try to login into my origin account and this popped up.(photo). But everytime I try to type in something I’m unable to clic
Oduvanchick [21]
You have to restart your computer or maybe use another internet browser to access the website your trying to reach
7 0
3 years ago
Text line breaks and returns are controlled using which tags?
eduard
<b></b> <span>element when used to strongly emphasize portions of text within a document.
<p></p> </span><span>tag defines a paragraph.
<ol></ol> </span><span>Defines an ordered list
<a></a> </span><span> tag defines a hyperlink</span>
5 0
3 years ago
Read 2 more answers
What is the name of a wireless network that allows phones and laptops to connect with pda's using bluetooth communications?
Jlenok [28]
Wireless Personal Area Netwrok (WPAN) or Personal Area Network (PAN)
4 0
3 years ago
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