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Answer:
There's a parking lot that is 600m² big. The lot must be able to hold at least 3 buses and 10 cars.
Each car takes up 6m² and each bus takes up 30m².
However, there can only be 60 vehicles in the lot at any given time.
The cost to park in the lot is $2.50 per day for cars and $7.50 per day for buses. The lot must make at least $75 each day to break even.
What is a possible car to bus ratio that would allow the lot to make profit?
Answer:
Here is the Python program:
small_container = int(input("Enter the number of small containers you recycled?"))
large_container = int(input("Enter the number of large containers you recycled?"))
refund = (small_container * 0.10) + (large_container * 0.25)
print("The total refund for returning the containers is $" + "{0:.2f}".format(float(refund)))
Explanation:
The program first prompts the user to enter the number of small containers. The input value is stored in an integer type variable small_container. The input is basically an integer value.
The program then prompts the user to enter the number of large containers. The input value is stored in an integer type variable large_container. The input is basically an integer value.
refund = (small_container * 0.10) + (large_container * 0.25) This statement computers the refund that will be recieved for returning the small and larger containers. The small containers holding one litre or less have a $0.10 deposit so the number of small containers is multiplied by 0.10. The large containers holding more than one litre have a $0.25 deposit so the number of large containers is multiplied by 0.25. Now both of these calculated deposits of containers of each side are added to return the refund that will be received for returning these containers. This whole computation is stored in refund variable.
print("The total refund for returning the containers is $" + "{0:.2f}".format(float(refund))) This print statement displays the refund in the format given in the question. The output includes a $ sign and displays exactly two decimal places by using {0:.2f} where .2f means 2 decimal places after the decimal point. Then the output is represented in floating point number using. format(float) is used to specify the output type as float to display a floating point refund value up to 2 decimal places.
Answer:
The answer is "Option A".
Explanation:
The dynamic search ads also known as interactive contextual ads, that utilizes google advanced website browsing technologies to dynamically address relevant results requests based on the quality of a chain's website. These ads are beneficial for strategies, and other choices were wrong which can be described as follows:
- In option B, It helps to upload all the dynamic search ads URLs quickly.
- In option C, It helps to control computer service.
- In option D, It increases the network traffic.
Answer:
/*
I don't know what language you're using, so I'll write it in javascript which is usually legible enough.
*/
console.log(buildSequence(30));
function buildSequence(maxVal){
maxVal = Math.abs(maxVal);
var n, list = [];
for(n = 1; n < maxVal; n++){
/*
to check for odd numbers, we only need to know if the last bit
is a 1 or 0:
*/
if(n & 1){ // <-- note the binary &, as opposed to the logical &&
list[list.length] = n;
}else{
list[list.length] = -n;
}
}
return list.implode(',');
}