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3 years ago

Solve for x. Write both solution, separated by a comma. 4x^2-x-3=0.

Mathematics

2 answers:

lukranit [14]3 years ago

7 0

Answer:

Step-by-step explanation:

4x² - x - 3 = 0

4x² + 3x - 4x - 3 = 0

xx(4x + 3) - 4x - 3 = 0

xx(4x + 3) - (4x + 3) = 0

(4x + 3) × (x - 1) = 0

4x + 3 = 0 → x = -3/4

x - 1 = 0 → x = 1

Hope this helps! :)

Step2247 [10]3 years ago

6 0

Answer:

x = -3/4, 1

Step-by-step explanation:

Factor left side of the equation.

(4x + 3)(x - 1) = 0

Set factors equal to 0.

4x + 3 = 0

4x = -3

x = -3/4

x - 1 = 0

x = 1

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Let t = number of hours

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There are 15 pieces of fruit of bowl and six our apples what percent are apples.

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3 years ago

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OPEN ENDED QUESTION

posledela

Answer: I hope this helps :)

Substitution: 45+15(6-1)

Simplify: 120

Step-by-step explanation:

Calculate within parenthases (6-1) =5 =45+15(5)

Multiply left to right 15(5)=75 =45+75

Add leftg to right 45+75=120

Answer = 120

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3 years ago

⦁ Determine if the equation represents a direct variation. .8x = 1.6y ⦁ Suppose y varies directly with x. Write a direction vari

Mkey [24]

Part A:

Given that

$0.8x=1.6y\Rightarrow x= \frac{1.6}{0.8} y=2y$

Thus, x = ky where k = 2.

Therefore, the given equation is a direct variation.

Part B:

If y varies directly as x, then y = kx.

Given that y = 5 when x = 2, then

$5=2k \\ \\ \Rightarrow k=\frac{5}{2} =2.5 \\ \\ \Rightarrow y=2.5x$

When x = 12, y = 2.5(12) = 30.

Part C:

If y varies directly as x, then y = kx.

Given that y = 9 when x = -6, then

$9=-6k \\ \\ \Rightarrow k=-\frac{9}{6} =-\frac{3}{2} \\ \\ \Rightarrow y=-\frac{3}{2}x$

It can be seen that the equation above satisfies all the rows of the given table, therefore, y varies with x for the data in the question and the equation for the direct variation is $y=-\frac{3}{2}x$

Part 4:

If y varies directly as x, then y = kx.

Given that y = 1 when x = -2, then

$1=-2k \\ \\ \Rightarrow k=-\frac{1}{2} \\ \\ \Rightarrow y=-\frac{1}{2}x$

It can be seen that the equation above does not satisfies the other rows of the given table, therefore, y does not vary with x for the data in the question.

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