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Karo-lina-s [1.5K]
2 years ago
12

The letter P on the number line below represents the number

Mathematics
1 answer:
belka [17]2 years ago
7 0
54:67 34333:57643;7 (5577+DJ ) %hhc
You might be interested in
Find the sum:(11x+3)+(x+-5)
VikaD [51]

Answer:

12−2

Step-by-step explanation:

Simplify,

(11+3)+(−5)

11+3+−5

Subtract,

11+3+−5

11−2+

Combine like terms,

11−2+

12−2

Since we can't go any further, the solution is,

12−2

6 0
3 years ago
Mark wants to know how many families in his neighborhood plan to attend the neighborhood party. He puts all 80 of the neighborho
bonufazy [111]

Answer:

A. No, this is not a valid inference because he asked only 20 families

Step-by-step explanation:

You cannot assume that those are the only families that would want to go; you have to ask all the families.

8 0
3 years ago
Read 2 more answers
What is a description of an undefined term?
alukav5142 [94]

Answer:

In Geometry, we have several undefined terms: point, line and plane. From these three undefined terms, all other terms in Geometry can be defined. In Geometry, we define a point as a location and no size. ... And the third undefined term is the line.

Step-by-step explanation:

6 0
3 years ago
Factor each polynomial. Look for a GCF first
weeeeeb [17]

Answer:

20. x\left(x-6\right)\left(x+8\right)

22. 2\left(x+1\right)\left(x+4\right)

24. 5m\left(m-1\right)\left(m+7\right)

Step-by-step explanation:

20. x^3+2x^{2} -48x

The GCF is x, so you group it out of the equation first.

x(x^{2} +2x-48)

Then, you find 2 numbers that will equal to 2 when you add them and will equal to -48 when you multiply them.

?+?=2\\?*?=-48

The two numbers would be -6 and 8. You then differentiate the squares.

x\left(x-6\right)\left(x+8\right)

22. 2x^{2} +10x+8

The GCF is 2, so you must group it out.

2(x^{2} +5x+4)

Find the two numbers that will equal to 5 when you add them and will equal to 4 when you multiply them.

?+?=5\\?*?=4

The two numbers would be 1 and 4. Finally, differentiate the squares.

2\left(x+1\right)\left(x+4\right)

24. 5m^{3} +30m^2-35m

The GCF is 5m, so you must group it out.

5m(m^2+6m-7)

Find the two numbers that will equal to 6 when you add them and will equal to -7 when you multiply them.

?+?=6\\?*?=-7

The two numbers would be -1 and 7. Finally, differentiate the squares.

5m\left(m-1\right)\left(m+7\right)

7 0
2 years ago
What is the end behavior in the function y=2x^3-x
sasho [114]

Answer:

Step-by-step explanation:

When a question asks for the "end behavior" of a function, they just want to know what happens if you trace the direction the function heads in for super low and super high values of x. In other words, they want to know what the graph is looking like as x heads for both positive and negative infinity. This might be sort of hard to visualize, so if you have a graphing utility, use it to double check yourself, but even without a graph, we can answer this question. For any function involving x^3, we know that the "parent graph" looks like the attached image. This is the "basic" look of any x^3 function; however, certain things can change the end behavior. You'll notice that in the attached graph, as x gets really really small, the function goes to negative infinity. As x gets very very big, the function goes to positive infinity.

Now, taking a look at your function, 2x^3 - x, things might change a little. Some things that change the end behavior of a graph include a negative coefficient for x^3, such as -x^3 or -5x^3. This would flip the graph over the y-axis, which would make the end behavior "swap", basically. Your function doesn't have a negative coefficient in front of x^3, so we're okay on that front, and it turns out your function has the same end behavior as the parent function, since no kind of reflection is occurring. I attached the graph of your function as well so you can see it, but what this means is that as x approaches infinity, or as x gets very big, your function also goes to infinity, and as x approaches negative infinity, or as x gets very small, your function goes to negative infinity.

6 0
3 years ago
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